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Arada [10]
3 years ago
7

An air-track glider attached to a spring oscillates between the 12.0 cm mark and the 54.0 cm mark on the track. The glider compl

etes 13.0 oscillations in 39.0 s .What is the angular frequency of the oscillations?
Physics
1 answer:
Alina [70]3 years ago
6 0

Answer:

ω= 2.095rad/sec

Explanation:

angular frequency(ω)=2πf

F is the frequency

Frequency of an oscillation is the number of cycles completed per second. One oscillation represents 1cycle. Thus for 13 oscillations, the glider completes 13 cycles.

F= 13/39 =\frac{1}{3}Hz

angular frequency(ω)=2πf

angular frequency(ω)=2π * \frac{1}{3}

   = 2*\frac{22}{7}*\frac{1}{3}rad/sec

 ω= 2.095rad/sec

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