Question

An air-track glider attached to a spring oscillates between the 12.0 cm mark and the 54.0 cm mark on the track. The glider completes 13.0 oscillations in 39.0 s .What is the angular frequency of the oscillations?

Answer 1

Answer:

ω= 2.095rad/sec

Explanation:

angular frequency(ω)=2πf

F is the frequency

Frequency of an oscillation is the number of cycles completed per second. One oscillation represents 1cycle. Thus for 13 oscillations, the glider completes 13 cycles.

F= 13/39 =$\frac{1}{3}$Hz

angular frequency(ω)=2πf

angular frequency(ω)=2π * $\frac{1}{3}$

   = 2*$\frac{22}{7}$*$\frac{1}{3}$rad/sec

 ω= 2.095rad/sec