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2 years ago

Provide 2 important pitching tips you can tell someone else. softball

1 answer:

5 0

I know you only need two, but here are some options to choose from.

Tip 1 - throwing a fastball. Use two points to keep your arm properly aligned your biceps brush your ear at the top of the backswing, and your pitching hand brushes your hip at release.

Tip 2 - throwing a curveball. Pictures should know that in order to maximize your curves, you should visualize a series of dots from the mound to the outside corner of the plate. Pitch along those dots.

Tip 3 - throwing a fast pitch rise. It’s possible that your wrist snap may be sideways. Play with different grips or finger pressures and try to relax them.

Tip 4 - throwing a change-up. Don’t always throw the change-up in a given situation. Make sure to change your pitch selection.

Tip 5 - throwing a drop-ball. Keep your pitching arm close to your body to avoid injury.

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A car battery with a 12 V emf and an internal resistance of 0.11 Ω is being charged with a current of 56 A. What are (a) the pot

denpristay [2]

Answer:

Part a)

V = 18.16 V

Part b)

$P_r = 345 Watt$

Part c)

P = 672 Watt

Part d)

V = 5.84 V

Part e)

$P_r = 345 Watt$

Explanation:

Part a)

When battery is in charging mode

then the potential difference at the terminal of the cell is more than its EMF and it is given as

$\Delta V = E + i r$

here we have

$E = 12 V$

$i = 56 A$

$r = 0.11$

now we have

$\Delta V = 12 + (0.11)(56) = 18.16 V$

Part b)

Rate of energy dissipation inside the battery is the energy across internal resistance

so it is given as

$P_r = i^2 r$

$P_r = 56^2 (0.11)$

$P_r = 345 W$

Part c)

Rate of energy conversion into EMF is given as

$P_{emf} = i E$

$P_{emf} = (56)(12)$

$P_{emf} = 672 Watt$

Now battery is giving current to other circuit so now it is discharging

now we have

Part d)

$V = E - i r$

$V = 12 - (56)(0.11)$

$V = 12 - 6.16 = 5.84 V$

Part e)

now the rate of energy dissipation is given as

$P_r = i^2 r$

$P_r = 56^2 (0.11)$

$P_r = 345 W$

7 0

2 years ago

A projectile is launched at an angle of 29 degrees above the horizontal with an initial velocity of 36.6 at an unknown height.

fgiga [73]

The vertical velocity of the projectile upon returning to its original is 17. 74 m/s

<h3>How to determine the vertical velocity</h3>

Using the formula:

Vertical velocity component , Vy = V * sin(α)

Where

V = initial velocity = 36. 6 m/s

α = angle of projectile = 29°

Substitute into the formula

Vy = 36. 6 * sin ( 29°)

Vy = 36. 6 * 0. 4848

Vy = 17. 74 m/s

Thus, the vertical velocity of the projectile upon returning to its original is 17. 74 m/s

Learn more about vertical velocity here:

brainly.com/question/24949996

#SPJ1

8 0

1 year ago

What dose nuclear reactions produce?

aleksandrvk [35]

Answer:

a new chromebook for you and you will get to know the other one that

7 0

2 years ago

If a ball is tossed straight up into the air, at what position is its potential energy the greatest?

krok68 [10]

A. when it reaches the top of its flight

potential energy increases as the height of the object does, and the highest point of a ball's flight is when it reaches the top.

4 0

3 years ago

Read 2 more answers

The combination of all forces that act on an object are (2 points)

qaws [65]

Answer:

A) The net force

Explanation:

If two forces of equal strength act on an object in opposite directions, the forces will cancel, resulting in a net force of zero and no movement.

5 0

3 years ago