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Novosadov [1.4K]
3 years ago
15

Provide 2 important pitching tips you can tell someone else. softball

Physics
1 answer:
sveticcg [70]3 years ago
5 0
I know you only need two, but here are some options to choose from.

Tip 1 - throwing a fastball. Use two points to keep your arm properly aligned your biceps brush your ear at the top of the backswing, and your pitching hand brushes your hip at release.

Tip 2 - throwing a curveball. Pictures should know that in order to maximize your curves, you should visualize a series of dots from the mound to the outside corner of the plate. Pitch along those dots.

Tip 3 - throwing a fast pitch rise. It’s possible that your wrist snap may be sideways. Play with different grips or finger pressures and try to relax them.

Tip 4 - throwing a change-up. Don’t always throw the change-up in a given situation. Make sure to change your pitch selection.

Tip 5 - throwing a drop-ball. Keep your pitching arm close to your body to avoid injury.
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A liter is the same as a cubic meter. <br> a. True<br> b. False
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It is false ...........
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The table below shows the acceleration of gravity on different bodies in the
Aloiza [94]

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Pluto

because the the gravitation strength is small, so it will be accelerating slow

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Taylor Swift weighing 794 N gets on an elevator. The elevator uses 313 W of power to lift the person 22.0 m. How much time did t
mezya [45]

Answer:

55.80s

Explanation:

Power is calculated using the expression

Power = Work done/Time

Workdone= Force ×distance

Workdone = 794×22

Work done = 17468Joules

From the power formula

Time = Workdone/Power

Time = 17468/313

Time = 55.80seconds

The elevator takes 55.80seconds to life the Taylor

3 0
3 years ago
Consider a compact car that is being driven
aliina [53]

Answer:

Height h = 37.8 m

Explanation:

Given :

Velocity of car (v) = 98 km / h

Acceleration of gravity = 9.8 m/s²

Computation:

Acceleration of gravity = 9.8 m/s²

Acceleration of gravity = (98)(1,000 m / 3,600 s)

Acceleration of gravity = 27.22 m/s

By using law of conservation of energy ;

(1/2)mv² = mgh

h = v² / 2g

h = 27.22² / 2(9.8)

Height h = 37.8 m

5 0
3 years ago
A brick lands 10.1 m from the base of a building. If it was given an initial velocity of 8.6 m/s [61º above the horizontal], how
Montano1993 [528]
<h2>Answer: 10.52m</h2><h2 />

First, we have to establish the <u>reference system</u>. Let's assume that the building is on the negative y-axis and that the brick was thrown at the origin (see figure attached).

According to this, the initial velocity V_{o} has two components, because the brick was thrown at an angle \alpha=61\º:

V_{ox}=V_{o}cos\alpha   (1)

V_{ox}=8.6\frac{m}{s}cos(61\º)=4.169\frac{m}{s}  (2)

V_{oy}=V_{o}sin\alpha   (3)

V_{oy}=8.6\frac{m}{s}sin(61\º)=7.521\frac{m}{s}   (4)

As this is a projectile motion, we have two principal equations related:

<h2>In the x-axis: </h2>

X=V_{ox}.t  (5)

Where:

X=10.1m is the distance where the brick landed

t is the time in seconds

If we already know X and V_{ox}, we have to find the time (we will need it for the following equation):

t= \frac{X}{ V_{ox}}  (6)

t=2.42s  (7)

<h2>In the y-axis: </h2>

-y=V_{oy}.t+\frac{1}{2}g.t^{2}   (8)

Where:

y is the height of the building (<u>in this case it has a negative sign because of the reference system we chose)</u>

g=-9.8\frac{m}{s^{2}} is the acceleration due gravity

Substituting the known values, including the time we found on equation (7) in equation (8), we will find the height of the building:

-y=(7.521\frac{m}{s})(2.42s)+\frac{1}{2}(-9.8\frac{m}{s^{2}}).(2.42s)^{2}   (9)

-y=-10.52m   (10)

Multiplying by -1 each side of the equation:

y=10.52m >>>>This is the height of the building

3 0
3 years ago
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