Answer:
1.53 g
Explanation:
Given,
Initial speed = 30 m/s
Final speed = 0 m/s
Period of stretch, t = 2 s
average deceleration = ?
we know


a = -15 m/s²
Deceleration of the jumper = 15 m/s²
Deceleration in terms of g


Hence, the deceleration of the jumper is equal to 1.53 g
Answer: The minimum kinetic energy Kmin is 1.3 × 10^-13 J
Explanation: Please see the attachments below
Answer:
The velocity of the light will be 1.0c only
Explanation:
The velocity of the light measured in the case given in question will be 1.0c only.
This is due to the fact that the velocity of light is never relative. The velocity of the light is maximum
The velocity of the light cannot be scaled down in no case
Thus, the velocity of the light remains as constant.
Hence, the velocity of the light measured will be 1.0c although the ships have relative velocity.
Answer:

Explanation:
Let the length of the string is L.
Let T be the tension in the string.
Resolve the components of T.
As the charge q is in equilibrium.
T Sinθ = Fe ..... (1)
T Cosθ = mg .......(2)
Divide equation (1) by equation (2), we get
tan θ = Fe / mg




As θ is very small, so tanθ and Sinθ is equal to θ.

