4t=r
a=pir^2
sub 4t for r
a=pi(4t)^2
a=pi16t^2
a(t)=16pi(t^2)
A. a(t)=16pi(t^2)
B. sub 4 for t
a(4)=16pi4^2
a(4)=16pi16
a(4)=16*16*3.14
a(4)=803.84 square units
A. a(t)=16pi(t^2)
B. 803.84 square units
Answer:
B, C, and E
Step-by-step explanation:
In order for a function to be a function, an ordered pair cannot be on the same x coordinate
R = A / tetha
70° × pi/180 = radian
radian = 1.222 rad
3 = A / 1.222
Arc = 3.7 meter
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