Answer: Kelsey had $65 to spend on books. Each book cost $5.50, and there was a $7.50 fee for shipping. She let b equal the number of books she can purchase
Step-by-step explanation:
Answer:
Mean: 49
Median: 41
Mode: 45
Range: 70
Step-by-step explanation:
To find the mean: add up all the numbers, then divide by how many numbers there are.
To find the median:
Arrange your numbers in numerical order.
Count how many numbers you have.
If you have an odd number, divide by 2 and round up to get the position of the median number.
If you have an even number, divide by 2. Go to the number in that position and average it with the number in the next higher position to get the median.
To find the mode: The mode of a data set is the number that occurs most frequently in the set.
To find the range: The range is the difference between the smallest and highest numbers in a list or set. To find the range, first put all the numbers in order. Then subtract (take away) the lowest number from the highest.
Answer:
Step-by-step explanation:
Given:
∠DCE ≅ ∠DEC
∠B ≅ ∠F
DF ≅ BD
To prove:
ΔABC ≅ ΔGFE
Solution:
Statements Reasons
1). ∠DCE ≅ ∠DEC 1). Given
2). ∠ACB ≅ ∠GEF 2). Vertically opposite angles to the
congruent angles.
3). ∠B ≅ ∠F 3). Given
4). DB ≅ DF 4). Given
5). DC + CB ≅ DE + EF 5). Segment addition postulate
6). DC ≅ DE 6). Property of isosceles triangle
7). CB ≅ EF 7). Transitive property
8). ΔABC ≅ ΔGFE 8). ASA property of congruence
Answer:
140
Step-by-step explanation:
To construct a subset of S with said property, we have two choices, include 3 in the subset or include four in the subset. These events are mutually exclusive because 3 and 4 can not both be elements of the subset.
First, let's count the number of subsets that contain the element 3.
Any of such subsets has five elements, but since 3 is already an element, we only have to select four elements to complete it. The four elements must be different from 3 and 4 (3 cannot be selected twice and the condition does not allow to select 4), so there are eight elements to select from. The number of ways of doing this is 
.
Now, let's count the number of subsets that contain the element 4.
4 is already an element thus we have to select other four elements . The four elements must be different from 3 and 4 (4 cannot be selected twice and the condition does not allow to select 3), so there are eight elements to select from, so this can be done in ways.
We conclude that there are 70+70=140 required subsets of S.
