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DanielleElmas [232]
3 years ago
9

The rate traveled from Amarillo to Austin by a bus averages 60 miles per hour. The bus arrived in Austin after eight hours of tr

avel. An automobile averages 48 miles per hour. Using the inverse variation relationship, show what the time would be for the automobile to complete the trip. 14.4 hours 12 hours 10 hours
Physics
1 answer:
jeyben [28]3 years ago
3 0

Answer:

the car would arrive after 10 hr to Austin.

Explanation:

bus average from amarllo to austin = 60 miles per hour

time takne by bus to reach austin = 8 hr

automobile average from amarllo to austin = 60 miles per hour

from the information given in the question:

60 mph ---    8 h

48 mph ---  x h

By using The inverse variation:

60 : 48 = x : 8

60* 8 = 48* x

480 = 48*x

x = 480/48

x = 10 h

the car would arrive after 10 hr to Austin.

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Answer:

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Explanation:

We can use Newton's Universal Law of Gravitation to solve this problem:

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3.6=6.67\cdot10^{-11}\frac{m}{(2,400,000)^2},

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(a) The required parameter:

The final speed of the two sleds

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Where;

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v₃' = The final velocity of the cat

Plugging in the values gives;

22.7 kg × 0 + 3.63 × 0 = 22.7 × v₁' + 3.63 × 3.05

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v₁' =  -3.63 × 3.05/22.7 ≈ -0.49

The final velocity of the ice sled on the left, v₁' ≈ -0.49 m/s (opposite to the direction to the motion of the cat)

The final speed ≈ 0.49 m/s

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By conservation of momentum law,  m₂ × v₂ + m₃ × v₃ = m₂ × v₂' + m₃ × v₃'

Where;

v₂' = The final velocity of the ice sled on the right

v₃' = The final velocity of the cat

Plugging in the values gives;

22.7 kg × 0 + 3.63 × 0 = 22.7 × v₂' + 3.63 × 3.05

∴  22.7 × v₂'  = -3.63 × 3.05

v₂' =  -3.63 × 3.05/22.7 ≈ -0.49

The final velocity of the ice sled on the right = -0.49 m/s (opposite to the direction to the motion of the cat)

The final speed ≈ 0.49 m/s

(b) The required parameter;

The impulse of the force

The impulse on the cat = Mass of the cat × Change in velocity

The change in velocity, Δv = Initial velocity - Final velocity

Where;

The initial velocity = The velocity of the cat before it lands = 3.05 m/s

The final velocity = The velocity of the cat after coming to rest =

∴ Δv = 3.05 m/s - 0 = 3.05 m/s

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(c) The required information

The average velocity

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Where;

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We get;

F_{average} = \mathbf{\dfrac{Impulse}{\Delta \ t}}

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The average force on the right sled applied by the cat while landing, \mathbf{F_{average}} = 922.625 N

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