Answer:
a)
, b)
, c) D. The magnitud of the change in the ball's momentum.
Explanation:
a) The magnitude of the change in the ball's momentum is:
![\Delta p = (0.275\,kg)\cdot \left[\left(1.63\,\frac{m}{s} \right)-\left(-3.28\,\frac{m}{s} \right)\right]](https://tex.z-dn.net/?f=%5CDelta%20p%20%3D%20%280.275%5C%2Ckg%29%5Ccdot%20%5Cleft%5B%5Cleft%281.63%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%5Cright%29-%5Cleft%28-3.28%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%5Cright%29%5Cright%5D)

b) The change in the magnitude of the ball's momentum:
![\Delta p' = (0.275\,kg)\cdot \left[(1.63\,\frac{m}{s} )-(3.28\,\frac{m}{s} ) \right]](https://tex.z-dn.net/?f=%5CDelta%20p%27%20%3D%20%280.275%5C%2Ckg%29%5Ccdot%20%5Cleft%5B%281.63%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29-%283.28%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%20%5Cright%5D)

c) The magnitude of the change in the ball's momentum is more directly related to the net force acting on the ball, as it measures the effect of the force on change in ball's motion at measured time according to the Impact Theorem. So, the right answer is option D.
Answer:
c) The distance between the balls increases.
Explanation:
If you drop the balls at the same time, regardless of their masses they accelerate equally, since they will be in free fall.
However, if you drop one of the balls earlier, then that ball will gain velocity, whereas the second ball has zero initial velocity. At the time the second ball is dropped, both balls have the same acceleration but different initial velocities.
According to the below kinematics equation:

The initial velocity of the first ball will make the difference, and the first ball will travel a greater distance than the second ball. Hence, their distance increases.
Answer:
I think it's the most important part in this
When calculated energy transferred between objects use the definition of heat as