There doesn't seem to be any direct connection.
        
             
        
        
        
i know can you plzz help me with this question im sorry i didt answer your question i just need hel.
 
        
             
        
        
        
Answer:
a) 3.39 × 10²³ atoms
b) 6.04 × 10⁻²¹ J
c) 1349.35 m/s
Explanation:
Given:
Diameter of the balloon, d = 29.6 cm = 0.296 m
Temperature, T = 19.0° C = 19 + 273 = 292 K
Pressure, P = 1.00 atm = 1.013 × 10⁵ Pa
Volume of the balloon = 
or
Volume of the balloon = 
or
Volume of the balloon, V = 0.0135 m³
Now, 
From the relation, 
PV = nRT
where, 
n is the number of moles
R is the ideal gas constant = 8.314  kg⋅m²/s²⋅K⋅mol
on substituting the respective values, we get
1.013 × 10⁵ × 0.0135 = n × 8.314 × 292
or
n = 0.563
1 mol = 6.022 × 10²³ atoms
Thus, 
0.563 moles will have = 0.563 × 6.022 × 10²³ atoms = 3.39 × 10²³ atoms
b) Average kinetic energy = 
where,
Boltzmann constant,  
 
Average kinetic energy = 
or
Average kinetic energy = 6.04 × 10⁻²¹ J
c) rms speed = 
where, m is the molar mass of the Helium = 0.004 Kg
or
rms speed = 
or
rms speed = 1349.35 m/s
 
        
             
        
        
        
Answer:
The true course:  north of east
 north of east
The ground speed of the plane: 96.68 m/s
Explanation:
Given:
 = velocity of wind = = velocity of wind = 
 = velocity of plane in still air = = velocity of plane in still air = 
Assume:
 = resultant velocity of the plane = resultant velocity of the plane
 = direction of the plane with the east = direction of the plane with the east
Since the resultant is the vector addition of all the vectors. So, the resultant velocity of the plane will be the vector sum of the wind velocity and the plane velocity in still air.

Let us find the direction of this resultant velocity with respect to east direction:

This means the the true course of the plane is in the direction of  north of east.
 north of east.
The ground speed will be the magnitude of the resultant velocity of the plane.

Hence, the ground speed of the plane is 96.68 km/h.
 
        
             
        
        
        
Find Acceleration




Now
Using 1st equation of kinematics




