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My name is Ann [436]
3 years ago
13

Hydrogen bonds create unusual properties in water. What are they?

Physics
2 answers:
xeze [42]3 years ago
7 0

Answer:

High boiling and melting points: Hydrogen bonds increase the amount of energy required for phase changes to occur, thereby raising the boiling and melting points.

High specific heat: Hydrogen bonds increase the amount of energy required for molecules to increase in speed, thereby raising the specific heat.

Lower density as a solid than as a liquid: Hydrogen bonds increase the volume of the solid by holding molecules apart, thereby decreasing the density

High surface tension: Hydrogen bonds produce strong intermolecular  attractions, which increase surface tension

Explanation:

galina1969 [7]3 years ago
6 0

Answer:Liquid water is denser than Ice.

Ice float on top of liquid water.

Explanation:

Just trust me

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Can someone help me with a)​
Gnom [1K]

Answer:

what's your problem. How may I help you Buddy

3 0
3 years ago
A beam of light has a wavelength of 650 nm in vacuum. (a) What is the speed of this light in a liquid whose index of refraction
Lady_Fox [76]

Answer:

The speed of this light and wavelength in a liquid are 2.04\times10^{8}\ m/s and 442 nm.

Explanation:

Given that,

Wavelength = 650 nm

Index refraction = 1.47

(a). We need to calculate the speed

Using formula of speed

n = \dfrac{c}{v}

Where, n = refraction index

c = speed of light in vacuum

v = speed of light in medium

Put the value into the formula

1.47=\dfrac{3\times10^{8}}{v}

v=\dfrac{3\times10^{8}}{1.47}

v= 2.04\times10^{8}\ m/s

(b). We need to calculate the wavelength

Using formula of wavelength

n=\dfrac{\lambda_{0}}{\lambda}

\lambda=\dfrac{\lambda_{0}}{n}

Where, \lambda_{0} = wavelength in vacuum

\lambda = wavelength in medium

Put the value into the formula

\lambda=\dfrac{650\times10^{-9}}{1.47}

\lambda=442\times10^{-9}\ m

Hence, The speed of this light and wavelength in a liquid are 2.04\times10^{8}\ m/s and 442 nm.

3 0
3 years ago
A compressed spring has elastic potential energy. Please select the best answer from the choices provided T F
riadik2000 [5.3K]

Answer: True

Explanation:

As the spring is compressed, it acumulates energy, and the spring "wants to release that energy". This acumulated energy, (potential energy) is called "elastic potential energy" because of the elastical nature of the spring, that when compressed it wants to return to the original shape. So the sentence is true

6 0
3 years ago
What is the orbital period of a spacecraft in a low orbit near the surface of mars? The radius of mars is 3.4×106m.
valkas [14]
<h2>Answer: 56.718 min</h2>

Explanation:

According to the Third Kepler’s Law of Planetary motion<em> </em><em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”. </em>

In other words, this law states a relation between the orbital period T of a body (moon, planet, satellite) orbiting a greater body in space with the size a of its orbit.

This Law is originally expressed as follows:

T^{2}=\frac{4\pi^{2}}{GM}a^{3}   (1)

Where;

G is the Gravitational Constant and its value is 6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}

M=6.39(10)^{23}kg is the mass of Mars

a=3.4(10)^{6}m  is the semimajor axis of the orbit the spacecraft describes around Mars (assuming it is a <u>circular orbit </u>and a <u>low orbit near the surface </u>as well, the semimajor axis is equal to the radius of the orbit)

If we want to find the period, we have to express equation (1) as written below and substitute all the values:

T=\sqrt{\frac{4\pi^{2}}{GM}a^{3}}    (2)

T=\sqrt{\frac{4\pi^{2}}{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(6.39(10)^{23}kg)}(3.4(10)^{6}m)^{3}}    (3)

T=\sqrt{11581157.44 s^{2}}    (4)

Finally:

T=3403.1099s=56.718min    This is the orbital period of a spacecraft in a low orbit near the surface of mars

6 0
3 years ago
Which of the waves has the smallest amplitude?
balandron [24]

Answer:

I think its the Blue wave, im not sure so dont take my word for it.

Explanation:

3 0
3 years ago
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