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My name is Ann [436]
2 years ago
13

Hydrogen bonds create unusual properties in water. What are they?

Physics
2 answers:
xeze [42]2 years ago
7 0

Answer:

High boiling and melting points: Hydrogen bonds increase the amount of energy required for phase changes to occur, thereby raising the boiling and melting points.

High specific heat: Hydrogen bonds increase the amount of energy required for molecules to increase in speed, thereby raising the specific heat.

Lower density as a solid than as a liquid: Hydrogen bonds increase the volume of the solid by holding molecules apart, thereby decreasing the density

High surface tension: Hydrogen bonds produce strong intermolecular  attractions, which increase surface tension

Explanation:

galina1969 [7]2 years ago
6 0

Answer:Liquid water is denser than Ice.

Ice float on top of liquid water.

Explanation:

Just trust me

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If you drop a bar of soap on the floor is it clean or dirty
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Answer: Probably clean

Explanation: because it’s soap. If you want, just wash it off and it will be clean again

Hope this helps your soap problems! :b

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How do different factors affect solubility? Check all of the boxes that apply.
Karo-lina-s [1.5K]

Answer:

Explanation:

Solubility is affected by current concentration, mechanical disturbance, temperature and pressure. So the answers are:

- Increasing temperature decreases the solubility of gases.

- Stirring increases the solubility of solids.

- Increasing pressure increases the solubility of gases.

- Decreasing the amount of solvent decreases the solubility of solids, liquids, and gases.

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2 years ago
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Although the temperature gradient changes from region to region in the homosphere, there is one gradient that stays the same. it
bezimeni [28]

Answer: the answer is air gradient

Explanation:

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2 years ago
Alondra applies 24 N of force to the end of a stick (a type of lever) to open a can of paint.
Assoli18 [71]

Answer:

1/4

Explanation:

Mechanical Advantage = Load/Effort

Given

Effort applied = 24N

Load = 6N

Substitute

MA = 6/24

MA = 1/4

Hence the mechanical advantage is 1/4

8 0
2 years ago
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Determine the voltage ratings of the high-and-low voltage windings for this connection and the MVA rating of the autotransformer
SIZIF [17.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The High Voltage Rating for Auto - Transformer is 86kV

The  Low Voltage Rating for Auto - Transformer is 78kV

The MVA rating is 268.75MVA

b

The efficiency is 99.4%

Explanation:

From the question  we are given are given that

 The transformer has Mega Volt Amp rating of 25MVA

                          The frequency is 60-Hz

                           Voltage rating 8.0kV : 78kV

   The short circuit test gives : 453kV,321A,77.5kW

   The open circuit test gives : 8.0kV, 39.6A, 86.2kW

This can be represented on a diagram shown on the second uploaded image

From this diagram we can deduce that the The High Voltage Rating for Auto - Transformer is 86kV and the  Low Voltage Rating for Auto - Transformer is 78kV

 Now to obtain the current flowing through the 8kV  coil in the Auto-transformer we have

             \frac{25 \ Mega \ Volt\ Ampere }{8\ Kilo Volt}

The volt will cancel each other

             \frac{25*10^6}{8*10^3} =  3125\ A

 Now to obtain the required MVA rating we would multiply the value of Power obtained during the open circuit test by the value of the current calculated.we are making use of the power obtain during open circuit testing because the transformer at this point is not under any load.

MVA \ rating = (86*10^3)(3125) =268.75

We need to understand that Iron losses is due to open circuit test which has power = 86.2kW

While copper loss is due to short circuit test which has power = 77.5kW

The the current flowing through the secondary coil I_2 as shown in the circuit diagram can be obtained as

       I_2 = \frac{25*10^6}{78*10^3} =320.52 A \approx 321

Now the efficiency can be obtained as thus

           \frac{(operational \ MVA )*(Power factor \pf))}{(operational\  MVA (power factor pf) + copper loss + Iron loss)}*\frac{100}{1}

             =99.941%

8 0
2 years ago
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