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3 years ago

Hydrogen bonds create unusual properties in water. What are they?

Physics

2 answers:

xeze [42]3 years ago

7 0

Answer:

High boiling and melting points: Hydrogen bonds increase the amount of energy required for phase changes to occur, thereby raising the boiling and melting points.

High specific heat: Hydrogen bonds increase the amount of energy required for molecules to increase in speed, thereby raising the specific heat.

Lower density as a solid than as a liquid: Hydrogen bonds increase the volume of the solid by holding molecules apart, thereby decreasing the density

High surface tension: Hydrogen bonds produce strong intermolecular attractions, which increase surface tension

Explanation:

galina1969 [7]3 years ago

6 0

Answer:Liquid water is denser than Ice.

Ice float on top of liquid water.

Explanation:

Just trust me

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If a certain shade of blue has a frequency of 7.33 x 10^14Hz what is the energy of exactly one photon of this light. Is this as

geniusboy [140]

In calculating the energy of a photon of light, we need the relationship for energy and the frequency which is expressed as:

E=hv

where h is the Planck's constant (6.626 x 10-34 J s)and v is the frequency.
E = 6.626 x 10-34 J s (<span>7.33 x 10^14 /s) = 4.857 x 10^-19 J</span>

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3 years ago

Sarah observed that different kinds and amounts of fossils were present in a cliff behind her house. She wondered if changes in

MAXImum [283]

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3 years ago

When does a object have the greatest kinetic energy?

Rufina [12.5K]

When Object is at zero height, and there is no potential energy possess by the object then it exerts Greatest Kinetic energy in it's whole Journey

Hope this helps!

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3 years ago

To avoid an accident, a driver steps on the brakes to stop a 1000kg car traveling at 65km/h. If the braking distance is 35m, how

Alenkinab [10]

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3 years ago

A model rocket is launched straight upward with an initial speed of 56.5 m/s. It accelerates with a constant upward acceleration

marta [7]

Answer:

Maximum height reached by the rocket, h = 202.62 meters

Explanation:

It is given that,

Initial speed of the model rocket, u = 56.5 m/s

Constant upward acceleration, $a=1.96\ m/s^2$

Distance traveled by the engine until it stops, d = 198.8 m

Let v is the speed of the rocket when the engine stops. It can be calculated using the third equation of motion as :

$v=\sqrt{u^2+2ad}$

$v=\sqrt{(56.5)^2+2\times 1.96\times 198.8}$

v = 63.02 m/s

At the maximum height, v = 0 and the engine now decelerate under the action of gravity, a = -g. Let h is the maximum height reached by the rocket.

Again using third equation of motion as :

$v^2-u^2=-2gh$

$h=\dfrac{v^2-u^2}{-2g}$

$h=\dfrac{u^2}{2g}$

$h=\dfrac{(63.02)^2}{2\times 9.8}$

h = 202.62 meters

So, the maximum height reached by the rocket is 202.62 meters. Hence, this is the required solution.

3 0

3 years ago