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3 years ago

Help can someone do this for me

Chemistry

2 answers:

Pie3 years ago

7 0

Answer:

Magnesium Mg 12 12

Phosphorous P 15 15

Fluorine F 9 9

Iron Fe 26 26

Calcium Ca 20 20

Fluorine F 9 9

denis23 [38]3 years ago

4 0

Answer:

Magnesium Mg 12 12

Phosphorous P 15 15

Flourine F 9 9

Iron Fe 26 26

Calcium Ca 20 20

Flourine F 9 9

Explanation:

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Inventos de la física que estén entre los 800 años y 1500 Ocupó 15 porfa

a_sh-v [17]

Creados entre los 800 y los 1500 o inventos que llevan de creación ese tiempo,puedes ser la pregunta un poco específica?

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3 years ago

What is the IMA of the 1 st class lever in the graphic given? 2 3 0.5

Zina [86]

Answer:

I believe the answer isT 2.

Explanation:

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6 0

3 years ago

Read 2 more answers

Consider the half reactions below for a chemical reaction.

ladessa [460]

Answer:

Option A:

Zn(s) + Cu^(2+) (aq) → Cu(s) + Zn^(2+)(aq)

Explanation:

The half reactions given are:

Zn(s) → Zn^(2+)(aq) + 2e^(-)

Cu^(2+) (aq) + 2e^(-) → Cu(s)

From the given half reactions, we can see that in the first one, Zn undergoes oxidation to produce Zn^(2+).

While in the second half reaction, Cu^(2+) is reduced to Cu.

Thus, for the overall reaction, we will add both half reactions to get;

Zn(s) + Cu^(2+) (aq) + 2e^(-) → Cu(s) + Zn^(2+)(aq) + 2e^(-)

2e^(-) will cancel out to give us;

Zn(s) + Cu^(2+) (aq) → Cu(s) + Zn^(2+)(aq)

7 0

3 years ago

Which pair of reactants will undergo aldol condensation to produce methylvinyl ketone?

xenn [34]

When formaldehyde and acetone then react with each other( aldol condensation) then it will be formed methyl vinyl ketone.

In organic chemistry, an aldol condensation would be a condensation reaction in which an enol and enolate ion combines with a carbonyl chemical to produce a -hydroxy aldehyde or -hydroxy ketone, that is then dehydrated to produce a conjugated enone.

In aldol condensation, when formaldehyde and acetone then react with each other then it will be formed methyl vinyl ketone.

It can be written as

$CH_{2} O + CH_{3} COCH_{3}$ → $HOCH_{2} -CH_{2} -CO-CH_{3}$