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SSSSS [86.1K]
3 years ago
8

2. Determine the total pressure of a gas mixture that contains O2, N2, and He, if the partial

Chemistry
1 answer:
Burka [1]3 years ago
4 0

Answer:

978mmHg

Explanation:

The total pressure of a gas mixture is defined as the sum of the pressure of each gas in the mixture.

If the mixture of gases you have 200mmHg for O₂, 350mmHg for N₂ and 428mmHg for He, total pressure of the mixture is:

200mmHg + 350mmHg + 428mmHg = <em>978mmHg</em>

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3 years ago
What is the oxidation state of nitrogen in NaO2?<br> 1) +1<br> 2)+2<br> 3)+3<br> 4)+4
Mnenie [13.5K]

Answer:+3

Explanation: You have to find the oxidation number of N which is +3.

6 0
2 years ago
Liquid nitrogen has a density of 0.807 g/ml at –195.8 °c. if 1.00 l of n2(l) is allowed to warm to 25°c at a pressure of 1.00 at
Flauer [41]
Step 1: Change density from g/mL to g/L;

                                  0.807 g/mL  =  807 g/L

Step 2: Find Moles of N₂;
As,
             Density  =  Mass / Volume
Or,
             Mass  =  Density × Volume

Putting Values,

            Mass  =  807 g/L × 1 L

            Mass  =  807 g
Also,
            Moles  =  Mass / M.mass

Putting values,

            Moles  =  807 g / 28 g.mol⁻¹

            Moles  =  28.82 moles

Step 3: Apply Ideal Gas Equation to Find Volume of gas occupied,

As,
                        P V  =  n R T

                            V  =  n R T / P
Putting Values, remember! don't forget to change temperatue into Kelvin (25 °C + 273 = 298 K)

                 V  =  (28.82 mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 298 K) ÷ 1 atm

                 V  =  704.76 L
8 0
2 years ago
Cuando un gas que se encuentra a 20°c se calienta hasta los 40°c sin que varie su presion, su volumen se duplica
kati45 [8]

Answer:

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Explanation:

The equation below represent the ideal gases relationship

PV ÷ T = constant

Here

P denotes pressure,

V denotes volume,

T denotes temperature in degrees Kelvin

Now

20 ° c = 273 + 20

= 293 K

And,

40 ° c = 313 K

So,

V = Vo. 313 K ÷  293 K = 1.07 Vo

So,  the volume is NOT doubled.

In the case when the temperature would be determined in degrees celsius at 0 degrees so the volume would be zero

4 0
2 years ago
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This answer is True :)
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