All categories

3 years ago

A bicycle rider travels 50.0 Km in 2.5 hours. What is the cyclist's average speed?

Physics

2 answers:

vekshin13 years ago

5 0

<span>If you divide the numbers you will get on average of 20km</span>

Usimov [2.4K]3 years ago

5 0

TO get the answer first you have to get the equation which is V/T and 50.0 would be V= velocity and 2.5 would be T=time. You now do as the equation states and divide which will provide you with the answer of 20

You might be interested in

The wheel of a stationary exercise bicycle at your gym makes one rotation in 0.670 s. Consider two points on this wheel: Point P

defon

Answer:

0.938 m/s.

Explanation:

Given:

ω = 1 rev in 0.67 s

In rad/s,

1 rev = 2pi rad

ω = 2pi ÷ 0.67

= 9.38 rad/s

Rp = 10 cm

= 0.1 m

V = ω × r

= 9.38 × 0.1

= 0.938 m/s.

5 0

3 years ago

A −4.00 μC charge sits in static equilibrium in the center of a conducting spherical shell that has an inner radius 3.13 cm and

Mariulka [41]

Answer:

(a). The charge on the outer surface is −2.43 μC.

(b). The charge on the inner surface is 4.00 μC.

(c). The electric field outside the shell is $3.39\times10^{7}\ N/C$

Explanation:

Given that,

Charge q₁ = -4.00 μC

Inner radius = 3.13 m

Outer radius = 4.13 cm

Net charge q₂ = -6.43 μC

We need to calculate the charge on the outer surface

Using formula of charge

$q_{out}=q_{2}-q_{1}$

$q_{out}=-6.43-(-4.00)$

$q_{out}=-2.43\ \mu C$

The charge on the inner surface is q.

$q+(-2.43)=-6.43$

$q=-6.43+2.43= 4.00\ \mu C$

We need to calculate the electric field outside the shell

Using formula of electric field

$E=\dfrac{kq}{r^2}$

Put the value into the formula

$E=\dfrac{9\times10^{9}\times6.43\times10^{-6}}{(4.13\times10^{-2})^2}$

$E=33927618.73\ N/C$

$E=3.39\times10^{7}\ N/C$

Hence, (a). The charge on the outer surface is −2.43 μC.

(b). The charge on the inner surface is 4.00 μC.

(c). The electric field outside the shell is $3.39\times10^{7}\ N/C$

5 0

3 years ago

For a mass oscillating on a spring at what positions are (a) velocity and (b) acceleration of the mass have maximum valeus?

EleoNora [17]

Answer:

a)At the mean position

b)At the extremes positions

Explanation:

Given that mass is having oscillation motion.

We know that

1. At the mean position -The velocity of the mass is maximum and the acceleration of the mass is minimum.The net force on the mass will be zero.

2. At the extreme position-The velocity of the mass is minimum and the acceleration of the mass is maximum.The net force on the mass will not be zero.

Therefore

a)At the mean position

b)At the extremes positions

3 0

3 years ago

A girl dribbling a basketball is running a court that is 100 m in length. It takes her 4.2 seconds to reach the end of the court

Travka [436]

Divide the distance traveled by the time it took:

(100 m) / (4.2 s) ≈ 23.8 m/s

6 0

3 years ago

Which of these tools is used to measure temperature?

Feliz [49]

Answer:

D a thermometer

Explanation: It measures and track Celcius and Feirinheit.

3 0

3 years ago

Read 2 more answers