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Serga [27]
3 years ago
15

Convert 6:16 a.m. in military time​

Mathematics
1 answer:
Paraphin [41]3 years ago
5 0

Answer: It remains 6:16 am

Step-by-step explanation:

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Each sheet cake requires 3 cups of flour and 2 cups of sugar. If a bakery has 75 cups of flour, how many sheet cakes can be made
m_a_m_a [10]

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They can make 25 cakes

Step-by-step explanation:

75/3=25

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A company builds computers. it cost $6700
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Marissa is drawing coins from a bag that contains 5 pennies (yellow), 4 nickels (green), 5 dimes
Anna007 [38]

Answer:

\frac{4}{16}=\frac{1}{4}=0.25=25\%

Step-by-step explanation:

Total number of coins in the bag = 5 + 4 + 5 + 2 = 16 coins

Number of nickels in the bag = 4

We have to find the probability that Marissa draws a nickels from the bag.

Probability is defined as the ratio of Number of "Favorable Outcomes" to "Total number of possible outcomes"

In this case total number of possible outcomes is the total number of coins which is 16.

Favorable/Desires outcome is drawing a Nickle from the bag which are 4 in number. So, number of favorable outcomes is 4

Therefore, the probability that she will draw a nickel = \frac{4}{16}=\frac{1}{4}=0.25=25\%

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3 years ago
Helpppppp for brainliest
OlgaM077 [116]

Answer:

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According to a recent​ survey, the population distribution of number of years of education for​ self-employed individuals in a c
creativ13 [48]

Answer:

a) X: number of years of education

b) Sample mean = 13.5, Sample standard deviation = 0.4

c) Sample mean = 13.5, Sample standard deviation = 0.2

d) Decrease the sample standard deviation

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 13.5 years

Standard deviation,σ = 2.8 years

a) random variable X

X: number of years of education

Central limit theorem:

If large random samples are drawn from population with mean \mu and standard deviation \sigma, then the distribution of sample mean will be normally distributed with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

b) mean and the standard for a random sample of size 49

\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{49}} = 0.4

c) mean and the standard for a random sample of size 196

\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{196}} = 0.2

d) Effect of increasing n

As the sample size increases, the standard error that is the sample standard deviation decreases. Thus, quadrupling sample size will half the standard deviation.

7 0
3 years ago
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