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4 years ago

What happens to the atoms that make up hydrogen fuel as it burns?

Physics

1 answer:

ale4655 [162]4 years ago

4 0

Answer:

Get turned Into Water.

Explanation:

Combustion of Hydrogen involves combining oxygen and hydrogen essentially so when oxygen and hydrogen combine water is produced, following chemical equation describes this process.

$H_{2} +O_{2}=2(H_{2}O)$ .

Resulting product is two molecules of water.

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A man walks 6 km north, then turns and walks 6 km east what is the resultant and angle

gulaghasi [49]

That would depend on the man’s starting latitude. If 6.7 mi south of the north pole, for example, the resultant would be 6.7 mi due north of the starting point.

5 0

2 years ago

Bob is threatening Tom’s life with a giant laser with wavelength (650 nm), a distance (D = 10 m) from the wall James is shackled

Fittoniya [83]

Answer:

He should stand from the center of laser pointed on the wall at 1.3 m.

Explanation:

Given that,

Wave length = 650 nm

Distance =10 m

Double slit separation d = 5 μm

We need to find the position of fringe

Using formula of distance

$d\sin\theta=n\lambda$

$d\dfrac{y}{D}=n\lambda$

$y=\dfrac{\lambda D}{d}$

Put the value into the formula

$y=\dfrac{650\times10^{-9}\times10}{5\times10^{-6}}$

$y=1.3\ m$

Hence, He should stand from the center of laser pointed on the wall at 1.3 m.

8 0

3 years ago

A roller coaster has a mass of 275 kg. It sits at the top of a hill with height 85 m. If it drops from this hill, how fast is it

Minchanka [31]

kinematic equation

v squared = u squared + 2 a x s

v= sq root (0 + 2 10 x 65)

i thimk

4 0

3 years ago

Read 2 more answers

Hans Langseth's beard measured 5.33 m in 1927. Consider two charges, q1 = 2.42 nC and an unspecified charge, q2, are separated 5

schepotkina [342]

Answer:

-7.89 * 10^(-9) C

Explanation:

Parameters given:

q1 = 2.42 nC = 2.42 * 10^(-9) C

Distance between q1 and q2 = 5.33 m

q3 = 1.0 nC = 1 * 10^(-9) C

Distance between q1 and q3 = 1.9 m

Distance between q2 and q3 = 5.33 - 1.9 = 3.43 m

The net force acting on q3 is:

F = F(q1, q3) + F(q2, q3)

F = (k*q1*q3)/1.9² + (k*q2*q3)/3.43²

F = (9 * 10^(9) * 2.42 * 10^(-9) * 1 * 10^(-9))/3.61 + (9 * 10^(9) * q2 * 1 * 10^(-9))/11.7649

F = 6.033 * 10^(-9) + 0.765*q2

If the net force is zero:

0 = 6.033 * 10^(-9) + 0.765*q2

-0.765*q2 = 6.033 * 10^(-9)

=> q2 = -[6.033 * 10^(-9)]/0.765

q2 = -7.89 * 10^(-9) C

3 0

3 years ago

78 million in standard form

Leviafan [203]

Answer:

78 million in standard form is 78,000,000

6 0

3 years ago