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lutik1710 [3]
3 years ago
9

Help me please please

Physics
1 answer:
Vlada [557]3 years ago
6 0

Answer:

what question you wants

Explanation:

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Answer: 6.45 s

Explanation:

We have the following equation:

y=y_{o}+V_{o}t-\frac{1}{2}gt^{2} (1)

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y_{o}=75 m the height at the edge of the cilff

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0=75 m+(20 m/s)t-(4.9 m/s^{2})t^{2}  (2)

Rearranging the equation:

-(4.9 m/s^{2})t^{2} + (20 m/s)t + 75 m=0 (3)

At this point we have a quadratic equation of the form at^{2}+bt+c=0, and we have to use the quadratic formula if we want to find  t:

t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}  (4)

Where a=-4.9, b=20, c=75

Substituting the known values and choosing the positive result of the equation:

t=\frac{-20\pm\sqrt{20^{2}-4(-4.9)(75)}}{2(-4.9)}  (5)

t=6.453 s  This is the time it takes to the rock to hit the ground

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