Assuming you are talking about the atomic mass of calcium chloride...
M = n/V
M = 1/3.35
M = 0.298
Aluminium has 3 valance electrons in its outer shell. This means that it would need to give up 3 electrons to achieve a full octet.
Answer:
Four covalent bonds.
Explanation:
Hello,
In this case, given the attached picture in which you can find the Lewis dot structure for metanal (formaldehyde) we can see two C-H bonds and two C-O bonds via a double bond, thus, we can compute the type of each bond given the electronegativities of hydrogen, carbon and oxygen which are 2.1, 2.5 and 3.5 respectively:
![C-H=2.5-2.1=0.4\\C-O=3.5-2.5=1.0](https://tex.z-dn.net/?f=C-H%3D2.5-2.1%3D0.4%5C%5CC-O%3D3.5-2.5%3D1.0)
Thus, since both electronegativity difference are less 1.7 we infer that all of them are covalent, therefore, it has four covalent bonds, two C-H bonds and a double C-O bond.
Best regards-
Answer:
8.625 grams of a 150 g sample of Thorium-234 would be left after 120.5 days
Explanation:
The nuclear half life represents the time taken for the initial amount of sample to reduce into half of its mass.
We have given that the half life of thorium-234 is 24.1 days. Then it takes 24.1 days for a Thorium-234 sample to reduced to half of its initial amount.
Initial amount of Thorium-234 available as per the question is 150 grams
So now we start with 150 grams of Thorium-234
![150 \times \frac{1}{2}=24.1](https://tex.z-dn.net/?f=150%20%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%3D24.1)
![75 \times \frac{1}{2} =48.2](https://tex.z-dn.net/?f=75%20%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%20%3D48.2)
![34.5 \times \frac{1}{2} =72.3](https://tex.z-dn.net/?f=34.5%20%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%20%3D72.3)
![17.25 \times \frac{1}{2} =96.4](https://tex.z-dn.net/?f=17.25%20%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%20%3D96.4)
![8.625\times \frac{1}{2} =120.5](https://tex.z-dn.net/?f=8.625%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%20%3D120.5)
So after 120.5 days the amount of sample that remains is 8.625g
In simpler way , we can use the below formula to find the sample left
![A=A_{0} \cdot \frac{1}{2^{n}}](https://tex.z-dn.net/?f=A%3DA_%7B0%7D%20%5Ccdot%20%5Cfrac%7B1%7D%7B2%5E%7Bn%7D%7D)
Where
is the initial sample amount
n = the number of half-lives that pass in a given period of time.