2 years ago

The diagram shows an electromagnet made with copper wire, a steel nail,

Physics

2 answers:

Arlecino [84]2 years ago

7 0

Answer: C
Explanation: mark me please

rusak2 [61]2 years ago

7 0

Answer:

Its C

Explanation:

Just took test

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xz_007 [3.2K]

Answer:

The magnitude of the force between the two parallel wires is 0.0111 N.

Explanation:

Given;

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distance between the two wires, r = 0.03 m

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Therefore, the magnitude of the repulsive force between the two parallel wires is given by;

$F = \frac{\mu_0 I_1I_2l}{2\pi r}\\\\where;\\\mu_0 \ is \ permeability \ of \ free \ space = 4\pi *10^{-7} \ T.m/A \\\\F = \frac{(4\pi *10^{-7})(6.3)^2(42)}{2\pi (0.03)}\\\\F = 0.0111 \ N$

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3 years ago

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