Answer:
A. The bullet with 0.006kg has more energy
B. When the mass is doubled the kinetic energy increases
Explanation:
Kinetic energy increases when mass increases
kinetic energy increases when velocity increases
Answer:
Option A, Rule of law
Explanation:
The complete question is
Article 5 of the Fundamental Orders of Connecticut is MOST LIKELY related to which idea? A) rule of law B) personal freedom C) individual rights D) limited government
Solution
It is the first colonial constitution and also the first written constitution in America. It was first applicable to the inhabitants and Residents of Windsor, Harteford and Wethersfield
The article V of the Fundamental Orders of Connecticut is subjected to the Courte of Election of the towns. The towns were responsible for maintaining their own form of government through election with the involvement of general public. The 5th article is about the Judicial Department and the process of selection of judges who further governs the city. This abide by law of equality by vesting equal right of choosing the judges.
Solution
x(t) = 8 cos t, x(5π/6)= 8 cos(<span>5π/6)
</span>cos(5π/6)=cos(3π/6 + 2π/6 )=cos(π/3 +π/2)= - sin π/3 (cos (x+<span>π/2)= -sinx)
</span>x(t) = -8sin <span>π/3 = - 4 .sqrt3
</span>v(t) = -8sint = -8sin (π/3 +<span>π/2)= -8 cosπ/3 </span>(sin (x+π/2)= cosx)
v(t) =<span> -8 cosπ/3 = -8/2= - 4
</span>a(5π/6) = - 8cost = -(- sin π/3)= 4 .<span>sqrt3
</span>a(5π/6) = 4 .<span>sqrt3</span>
PART A)
Electrostatic potential at the position of origin is given by

here we have



now we have


Now work done to move another charge from infinite to origin is given by

here we will have

so there is no work required to move an electron from infinite to origin
PART B)
Initial potential energy of electron




Now we know



now by energy conservation we will have
So here initial total energy is sufficient high to reach the origin
PART C)
It will reach the origin
The lateral displacement is I don’t know tbh I think 16.8