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3 years ago

Which order shows decreasing momentum?

Physics

1 answer:

klio [65]3 years ago

4 0

Answer:

Explanation: Decreasing in velocity

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A. If a T-Rex runs 20 meters in 4 seconds, what is it’s average speed?

mariarad [96]

5m/s

100m

Explanation:

Average speed is sum of distance distance traveled in a given time by a body.

Average speed= $\frac{total distance covered}{time taken}$

Distance = 20m

time = 4s

Average speed = $\frac{20}{4}$ = 5m/s

For the spaceship;

Distance covered = speed x time

Speed = 50m/s

time = 2s

Distance covered = 50 x 2 = 100m

learn more:

Average speed brainly.com/question/5063905

#learnwithBrainly

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3 years ago

A sea breeze occurs because warm air rises on land and moves toward the ocean to cool. The cool air then moves from the ocean to

Norma-Jean [14]

Im going to go with a. True

7 0

3 years ago

Read 2 more answers

HELP PLZ ASAP!!

Andre45 [30]

1. The successful launch of communication satellites

2.More people will be interested in studying science

But science would probably be focused on space exploration and there will probably be less scientists in other fields such as chemistry.

5 0

3 years ago

Find the expression for the displacement covered in nth or in last one second

Natali [406]

Answer:

Snth = u + a/2 ( 2n - 1)

Explanation:

Do you need explanation based on graph, integration or other method?

3 0

3 years ago

A box rests on the (horizontal) back of a truck. The coefficient of static friction between the box and the surface on which it

vredina [299]

Answer:

The distance is 11 m.

Explanation:

Given that,

Friction coefficient = 0.24

Time = 3.0 s

Initial velocity = 0

We need to calculate the acceleration

Using newton's second law

$F = ma$ ...(I)

Using formula of friction force

$F= \mu m g$ ....(II)

Put the value of F in the equation (II) from equation (I)

$ma=\mu mg$ ....(III)

$a = \mu g$

Put the value in the equation (III)

$a=0.24\times9.8$

$a=2.352\ m/s^2$

We need to calculate the distance,

Using equation of motion

$s = ut+\dfrac{1}{2}at^2$

$s=0+\dfrac{1}{2}2.352\times(3.0)^2$

$s=10.584\ m\ approx\ 11\ m$

Hence, The distance is 11 m.

3 0

3 years ago