Answer:
F = 47261.5 N = 47.26 KN
Explanation:
First, we will calculate the deceleration of the bullet by using the third equation of motion:
where,
a = deceleration = ?
s = distace covered = 5.2 cm = 0.052 m
vf = final speed = 0 m/s
vi = initial speed = 640 m/s
Therefore,
negative sign shows deceleration.
Now for the force, we will use Newton's Second Law of Motion:
F = ma
where,
F = Force = ?
m = mass of bullet = 12 g = 0.012 kg
Therefore,
F = (0.012 kg)(3938461.5 m/s²)
<u>F = 47261.5 N = 47.26 KN</u>
Then, it's speed must be increased by 4 times.
As we know, K.E. α v²
Explanation:
u=0, g=9.8m/s², h=1.2m, v= ?.
from the formula => v²-u²=2gh
=> v²=2×9.8×1.2
=> v = √23.52
=> v = 4.84 m/s .
therefore, with 4.84 m/s the ball will hit the ground.
hope this helps you.
Answer:
The interference of two sound waves of similar amplitude but slightly different frequencies produces a loud-soft-loud oscillation we call <u>beats</u>.
Explanation:
When two objects vibrate at different frequencies, a fluctuating sound is heard, (loud-soft-loud). This phenomenon is known as beating. Loud sound is caused by constructive interference, and soft sound is caused by destructive interference.
You use the equation potential energy= mass x gravity x height. 10x2x9.8=196.