Two force always involved in using a machine are

Snorkeling by humans and elephants. When a person snorkels, the lungs are connected directly to the atmosphere through the snork

fgiga [73]

Answer:

2354.4 Pa

40221 Pa

Explanation:

$\rho$ = Density = 1000 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Depth

The pressure difference would be

$\Delta P=\rho gh\\\Rightarrow \Delta P=1000\times 0.24\times 9.81\\\Rightarrow \Delta P=2354.4\ Pa$

The pressure difference in the first case is 2354.4 Pa

$\Delta P=\rho gh\\\Rightarrow \Delta P=1000\times 4.1\times 9.81\\\Rightarrow \Delta P=40221\ Pa$

The pressure difference in the second case is 40221 Pa

7 0

3 years ago

You want to create a device to warm food that is safe. Which type of electromagnetic wave would be most useful to investigate? A

Liono4ka [1.6K]

The best type of electromagnetic wave to use to warm food that is safe would be the infrared wave. The correct answer is B.

8 0

3 years ago

Read 2 more answers

A ball is released from the top of a tower of height h meters. it takes T seconds to reach the ground . what is the position of

alekssr [168]

Answer:the

8/9 h

Explanation:

Height = 1/2 a T^2 now change to T/3

now height = 1/2 a (T/3)^2 = 1/9 1/2 a T^2 <===== it is 1/9 of the way down or 8/9 h

3 0

1 year ago

If the rectangular barge is 3.0 m by 20.0 m and sits 0.70 m deep in the harbor, how deep will it sit in the river?

leva [86]

The harbour contains salt water while the river contains fresh water. So assuming that the densities of fresh water and salt water are:

density (salt water) = 1029 kg / m^3

density (fresh water) = 1000 kg / m^3

The amount of water (in mass) displaced by the barge should be equal in two waters.

mass displaced (salt water) = mass displaced (fresh water)

Since mass is also the product of density and volume, therefore:

[density * volume]_salt water = [density * volume]_fresh water ---> 1

First we calculate the amount of volume displaced in the harbour (salt water):

V = 3.0 m * 20.0 m * 0.70 m

V = 42 m^3 of salt water

Plugging in the values into equation 1:

1029 kg / m^3 * 42 m^3 = 1000 kg/m^3 * Volume fresh water

Volume fresh water displaced = 43.218 m^3

Therefore the depth of the barge in the river is:

43.218 m^3 = 3.0 m * 20.0 m * h

h = 0.72 m (ANSWER)

8 0

3 years ago

Find the radius Rrigel of the star Rigel, the bright blue star in the constellation Orion that radiates energy at a rate of 2.7×

Zinaida [17]

Answer:

r = 1.61 x 10^{11} m

Explanation:

energy radiated (H) = 2.7 x 10^31 W

surface temperature (T) = 11,000 k

assuming ε = 1 and taking σ = 5.67 x 10^{-8} W/m^{2}.K^{4}

we can find the radius of the star from the equation below

H = A x ε x σ x T^{4}

where area (A) = 4 x π x r^{2} (assuming it is a sphere)

therefore the equation becomes

H = 4 x π x r^{2} x ε x σ x T^{4}

2.7 x 10^31 = 4 x π x r^{2} x 1 x 5.67 x 10^{-8} x (11,000)^{4}

r = $\sqrt{\frac{2.7 x 10^31}{4 x π x 1 x 5.67 x 10^{-8} x (11,000)^{4}} }$

r = 1.61 x 10^{11} m

4 0

3 years ago