<h3>
Answer:</h3>
CuO(s) + H₂(g) → Cu(s) + H₂O(l)
<h3>
Explanation:</h3>
- Assuming the reaction is the reduction of CuO by H₂
- Then the balanced equation for the reaction is;
CuO(s) + H₂(g) → Cu(s) + H₂O(l)
- The equation shows the reducing property of hydrogen gas, such that hydrogen reduces metal oxides such as copper(ii)oxide to the respective metals.
- The law of conservation requires chemical equations to be balanced so as the mass of reactants will be equal to that of products.
- In this case; there is 1 copper atom, 1 oxygen atom and 2 hydrogen atoms on both side of the equation and thus the equation is balanced.
1 liter = 2.11 pints
8 pints = 1 gallon
4900 L * (2.11 pints/1 L) * (1 gallon/8 pints) = 1292.375 gallons
4900 has 2 significant figures, so our final answer should have two. Your final answer is 1300 gallons.
Mass number = protons + neutrons
mass number = 5 + 7
mass number = 12
Answer:
When heated or cooled, matter can transform from one state to another. When you heat ice (a solid), it turns into water (a liquid). MELTING is the term for this transformation. When water is heated, it becomes steam (a gas).
Explanation:
i hope thats the answer you want
Answer:
131.5 kJ
Explanation:
Let's consider the following reaction.
CaCO₃(s) → CaO(s) + CO₂(g)
First, we will calculate the standard enthalpy of the reaction (ΔH°).
ΔH° = 1 mol × ΔH°f(CaO(s)) + 1 mol × ΔH°f(CO₂(g)
) - 1 mol × ΔH°f(CaCO₃(s)
)
ΔH° = 1 mol × (-634.9 kJ/mol) + 1 mol × (-393.5 kJ/mol) - 1 mol × (-1207.6 kJ/mol)
ΔH° = 179.2 kJ
Then, we calculate the standard entropy of the reaction (ΔS°).
ΔS° = 1 mol × S°(CaO(s)) + 1 mol × S°(CO₂(g)
) - 1 mol × S°(CaCO₃(s)
)
ΔS° = 1 mol × (38.1 J/mol.K) + 1 mol × (213.8 J/mol.K) - 1 mol × (91.7 J/mol.K)
ΔS° = 160.2 J/K = 0.1602 kJ/K
Finally, we calculate the standard Gibbs free energy of the reaction at T = 25°C = 298 K.
ΔG° = ΔH° - T × ΔS°
ΔG° = 179.2 kJ - 298 K × 0.1602 kJ/K
ΔG° = 131.5 kJ
