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stira [4]
3 years ago
14

A fair ground ride spins its occupants inside a flying saucer-shaped container. if the horizontal circular path the riders follo

w has an 8.00 m radius, at how many revolutions per minute will the riders be subjected to a centripetal acceleration whose magnitude is 1.50 times that due to gravity?
Physics
1 answer:
Licemer1 [7]3 years ago
6 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below is the solution:

 <span>centripetal accel = 1.5*g 
ω²r = 1.5*9.8m/s² 
ω² * 8m = 14.7 m/s² 
ω = 1.36 rad/s * 1rev/2πrads * 60s/min = 12.9 rpm</span>

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You need to consider the following:
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<span>
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 F = G * M1M2/r^2 
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3 years ago
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4 0
3 years ago
In a high school swim competition, a student takes 1.6 s to complete 1.5 somersaults. Determine the average angular speed of the
Rufina [12.5K]

Answer:

The  angular speed is w = 5.89 \ rad/s

Explanation:

From the question we are told that

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    The number of somersaults  is n  =  1.5

The total angular displacement during the somersault is mathematically represented as

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substituting values

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substituting values

         w =  \frac{9.426}{1.6}

          w = 5.89 \ rad/s

     

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3 years ago
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Answer:

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