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meriva
3 years ago
9

Which state of matter has particles with the greatest amount of kinetic energy?

Physics
1 answer:
dangina [55]3 years ago
6 0
A.) Gases have the greatest amount of Kinetic energy

Hope this helps!
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Which chemical can be toxic to the cells of it’s not removed?
masya89 [10]
Hey There,

Question: <span>Which chemical can be toxic to the cells of it’s not removed?

Answer: D. Carbon Dioxide

If This Helps May I Have Brainliest?</span>
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You have a mass of 60-kg, and you are facing your friend who has a mass of 100 kg. You skate towards
White raven [17]

Answer: My initial velocity is 5 m/s.

Explanation:

In this case, momentum can be conserved.

initial momentum = final momentum

Since both the bodies come to rest after collision,

Final momentum = 0

Let my velocity be v, and mass, m1 = 60 kg

Friend's mass, m2 = 100 kg

Friend's velocity, v2 = 3 m/s

Intial momentum = m1v + m2v2

= 60v + 300

Conserving momentum,

60v + 300 = 0

v= -5 m/s

( Negative sign indicates that me and my friend are moving in opposite directions that is towards each other)

4 0
3 years ago
Q1. After three half-lives of an isotope, 1 billion of the original isotope's atoms still remain in a certain amount of this ele
77julia77 [94]
 <span>If 1 eighth equals 1 billion 7 eighth equals 7 billion. 

The asker of the second question needs a tutorial in radiometric dating. There is little likelihood that the daughter isotope has the same atomic weight as the parent isotope. To measure the mass isotopes doesn't tell us how many atoms of each exist. To get around that let's pretend — which will likely serve the purpose ineptly intended — that the values give an the particle ratio, 125:875. 

The original parent isotope count was 125 + 875 = 1000. The remaining parent isotope is 125/1000 or 1/8. 1/8 = (1/2)^h, where h is the number of half-lives. 

h = log (1/8) ÷ log(1/2) = 3 

And 3 half-lives • 150,000 years/half-life = 450,000 years.</span>
5 0
3 years ago
How many molecules do we have for Na2Co3?
-BARSIC- [3]

105.9888 g/mol is the mass as far as i know, Don't know the amount of molecules tho.

mark me brainliestt :))

8 0
2 years ago
An 8 g bullet leaves the muzzle of a rifle with
Elena-2011 [213]

Answer: 1872 N

Explanation:

This problem can be solved by using one of the Kinematics equations and Newton's second law of motion:

V^{2}=V_{o}^{2} + 2ad (1)

F=ma (2)

Where:

V=611.9 m/s is the bullet's final speed (when it leaves the muzzle)

V_{o}=0 is the bullet's initial speed (at rest)

a is the bullet's acceleration

d=0.8 m is the distance traveled by the bullet before leaving the muzzle

F is the force

m=8 g \frac{1 kg}{1000 g}=0.008 kg is the mass of the bullet

Knowing this, let's begin by isolating a from (1):

a=\frac{V^{2}}{2d} (3)

a=\frac{(611.9 m/s)^{2}}{2(0.8 m)} (4)

a=234013.5063 m/s^{2} \approx 2.34(10)^{5} m/s^{2} (5)

Substituting (5) in (2):

F=(0.008 kg)(2.34(10)^{5} m/s^{2}) (6)

Finally:

F=1872 N

4 0
2 years ago
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