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nordsb [41]
3 years ago
10

17. The name of the reaction that produces esters is

Chemistry
2 answers:
AfilCa [17]3 years ago
6 0

Answer:

the name of reaction that produces esters is dehydration.

Scrat [10]3 years ago
6 0

Explanation:

The name of the reaction that produces esters is

=⟩C. radical initiated polymerization.

Hope it is helpful to you

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Forests are the only carbon sinks on Earth. Please select the best answer from the choices provided T F
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Which of the following statements is true?
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Identify the products of this single-replacement reaction between sulfuric acid and aluminum. Then balance the equation. (2 poin
jeka94

The products of this reaction between aluminum and sulfuric acid are two: hydrogen and aluminum sulfate.

<h3>What are the products in a reaction?</h3>

This concept refers to the substances obtained at the end of the reaction.

<h3>What does it mean to balance an equation?</h3>

It means to make sure there are the same molecules in the reactants and products.

<h3>What are the products in this reaction?</h3>
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  • H = Hydrogen

<h3>What is the balanced equation?</h3>

2Al + 3H2SO4 = Al2 (SO4)3 + 3H2

Learn more about chemical reaction in: brainly.com/question/3461108

7 0
2 years ago
Ammonia, nh3, is a weak base with a kb = 1.8 x 10-5. in a 0.8m solution of ammonia, which has a higher concentration: ammonia (n
insens350 [35]
Answer is: concentration ammonia is higher than concentration of ammonium ion.
Chemical reaction of ammonia in water: NH₃ + H₂O → NH₄⁺ + OH⁻.
Kb(NH₃) = 1,8·10⁻⁵.
c₀(NH₃) = 0,8 mol/L.
c(NH₄⁺) = c(OH⁻) = x.
c(NH₃) = 0,8 mol/L - x.
Kb = c(NH₄⁺) · c(OH⁻) / c(NH₃).
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solve quadratic equation: x = c(NH₄⁺) = 3,79·10⁻³ mol/L.
7 0
3 years ago
Draw the structure of the bromohydrin formed when (Z)-3-hexene reacts with Br2/H2O. Use the wedge/hash bond tools to indicate st
Ipatiy [6.2K]

Answer:

(3R,4R)-4-bromohexan-3-ol

Explanation:

In this case, we have  reaction called <u>halohydrin formation</u>. This is a <u>markovnikov reaction</u> with <u>anti configuration</u>. Therefore the halogen in this case "Br" and the "OH" must have <u>different configurations</u>. Additionally, in this molecule both carbons have the <u>same substitution</u>, so the "OH" can go in any carbon.

Finally, in the product we will have <u>chiral carbons</u>, so we have to find the absolute configuration for each carbon. On carbon 3 we will have an "R" configuration on carbon 4 we will have also an "R" configuration. (See figure 1)

I hope it helps!

5 0
3 years ago
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