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Alborosie
3 years ago
10

PLEASEE HELLLPPP mE WITH THE QUESTIONS I POSTE DIL MARK U THE BRAINLIEST I SWEAAARr

Chemistry
2 answers:
kvv77 [185]3 years ago
5 0

Answer:

PIEASE E first write question

qaws [65]3 years ago
4 0
I will see what I can do
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Who has taken chemistry, if you have I want to know how were you successful (if u were) because currently I am taking it and I’m
Andreas93 [3]

My number one tip is to STUDY! I know it sucks, but once you're in high school, it's going to become a part of your routine every single day. Even if you study right now, keep on doing it over and over and over. Trust me! It'll help. Also, get a tutor! Maybe someone you know is doing well and you could ask them to help, or you could ask a student who was in your class and passed. My number one advice is to just keep working hard. I get it; chemistry is HARD. You'll get there!

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3 years ago
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An aluminum plate is 78 cm wide and 35 cm long. The mass of the plate is 44,226 g. Determine its thickness. [The density of lead
Artemon [7]

Answer:

i try to solve it for you, and i aplode a similer question for you

Explanation:

6 0
3 years ago
The substance that is doing the dissolving is referred to as?
ella [17]

Answer:

hi! I'm pretty sure your answer is solvent!

Explanation:

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7 0
4 years ago
Help me plz promise I will mark u the brainiest
Sloan [31]

atom x is sodium and then the atom y is chlorine

8 0
3 years ago
A 50.0 mL of 0.88 M H2O2 and 10.0 mL of 0.50 M Fe(NO3)3 were combined and a temperature change of 7.47 was observed. The specifi
Shtirlitz [24]

Answer:

The heat of reaction -1.9 kilo Joules.

Explanation:

Volume of the hydrogen peroxide solution = 50.0 mL

Volume of the ferric nitrate solution = 10.0 mL

Total volume of the solution = 50.0 mL + 10.0 mL = 60.0 mL

Mass of the final solution = m

Density of water = density of the final solution = d = 1 g/mL

Mass=density\times Volume

m=1 g/ml\times 60.0 ml=60.0 g

Heat capacity of the mixture = c = 4.18 J/g°C

Change in temperature of the mixture = ΔT = 7.47°C

Heat absorbed by the mixture = Q

Q=mc\Delta T

Q=60.0 g\times 4.18 J/g ^oC\times 7.47 ^oC=1873.48 J=1.873 kJ\approx 1.9 kJ

Heat release due to reaction = -Q'

-Q' =Q (law of conservation of enrage)

Q'= -Q = -1.9 kJ

The heat of reaction -1.9 kilo Joules.

7 0
4 years ago
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