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Alborosie
3 years ago
10

PLEASEE HELLLPPP mE WITH THE QUESTIONS I POSTE DIL MARK U THE BRAINLIEST I SWEAAARr

Chemistry
2 answers:
kvv77 [185]3 years ago
5 0

Answer:

PIEASE E first write question

qaws [65]3 years ago
4 0
I will see what I can do
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5. Which is an example of inertia?
Hitman42 [59]

Answer:

Explanation:

D. When the truck driver slammed on the brakes, all the boxes in the back

of the truck slid forward.

6 0
3 years ago
How much voltage is required to run 1.6 A of current through a 240
pentagon [3]

Answer:

answer is not there

Explanation:

V=1.6×240

V=384volt

6 0
2 years ago
Automobile catalytic Converters use a platinum callus to reduce air pollution by changing emissions such as carbon monoxide CO2
natka813 [3]

Answer:

14 mol O₂

Explanation:

The reaction between CO and O₂ is the following:

CO + O₂ → CO₂

We balance the equation with a coefficient 2 in CO and CO₂ to obtain the same number of O atoms:

2CO + O₂ → 2CO₂

As we can see from the balanced equation, 1 mol of O₂ is required to react with 2 moles of CO. Thus, the conversion factor is 1 mol of O₂/2 mol CO. We multiply the moles of CO by the conversion factor to calculate the moles of O₂ that are required:

28 mol CO x 1 mol of O₂/2 mol CO = 14 mol O₂

6 0
2 years ago
Convert 600 m to mm.
anzhelika [568]

Answer:

600,000

Explanation:

In order to convert meters or metre to millimeter or millimetre, you must multiply the meter/metre by 1000. (Some countries say meter and others say metre.) Hope it helps! <3

5 0
3 years ago
You have a 100 ml stock solution of 100 mg/ml ampicillin in deionized water. You want to make 30 ml of 25 mg/ml ampicillin in de
Georgia [21]

Explanation:

Volume of the stock solution is V_{1} = ?

Initial concentration of ampicillin is M_{1} = 100 mg/ml

Final volume (V_{2}) = 30 ml

Final concentration of  ampicillin (M_{2}) = 25 mg/ml

Therefore, calculate the volume of given stock as follows.

              M_{1} \times V_{1} = M_{2} \times V_{2}

Now, putting the given values into the above formula as follows.

            M_{1} \times V_{1} = M_{2} \times V_{2}

            100 mg/ml \times V_{1} = 25 g/ml \times 30 ml    

                   V_{1} = 7.5 ml

Now, we will calculate the volume of water added into it as follows.

            Volume of water added = V_{2} - V_{1}

                                                  = 30 ml - 7.5 ml

                                                  = 22.5 ml

Thus, we can conclude that required solution is 22.5 ml of deionized water.

3 0
3 years ago
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