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Vanyuwa [196]
3 years ago
9

How many moles are there in 2.75L of a 2.0M solution

Chemistry
1 answer:
gtnhenbr [62]3 years ago
7 0
5.5 moles
2.0=x/2.75
2.0*2.75= x/2.75 (2.75)
5.5=x
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If a mixture containing 0.50 moles of N2 and 1.8 moles of H2 is allowed to react according to the equation N2 3H2 2NH3 Group of
Lelechka [254]

Answer: hydrogen is the limiting reactant.

Explanation:

We have the equation \text{N}_{2}+3\text{H}_{2} \longrightarrow 2\text{NH}_{3}.

This means that for every mole of nitrogen consumed, 3 moles of hydrogen are consumed.

  • Considering the nitrogen, the reaction can occur 0.50 times.
  • Considering the hydrogen, the reaction can occur 1.8/3 = 0.6 times.

Therefore, <u>hydrogen</u> is the limiting reactant.

7 0
2 years ago
When a mercury-202 nucleus is bombarded with a neutron, a proton is ejected. What element is formed?
Galina-37 [17]

That will make a gold-202 nucleus.

<h3>Explanation</h3>

Refer to a periodic table. The atomic number of mercury Hg is 80.

Step One: Bombard the \displaystyle ^{202}_{\phantom{2}80}\text{Hg} with a neutron ^{1}_{0}n. The neutron will add 1 to the mass number 202 of ^{202}_{\phantom{2}80}\text{Hg}. However, the atomic number will stay the same.

  • New mass number: 202 + 1 = 203.
  • Atomic number is still 80.

^{202}_{\phantom{2}80}\text{Hg} + ^{1}_{0}n \to ^{203}_{\phantom{2}80}\text{Hg}.

Double check the equation:

  • Sum of mass number on the left-hand side = 202 + 1 = 203 = Sum of mass number on the right-hand side.
  • Sum of atomic number on the left-hand side = 80 = Sum of atomic number on the right-hand side.

Step Two: The ^{203}_{\phantom{2}80}\text{Hg} nucleus loses a proton ^{1}_{1}p. Both the mass number 203 and the atomic number will decrease by 1.

  • New mass number: 203 - 1 = 202.
  • New atomic number: 80 - 1 = 79.

Refer to a periodic table. What's the element with atomic number 79? Gold Au.

^{203}_{\phantom{2}80}\text{Hg} \to ^{202}_{\phantom{2}79}\text{Au} + ^{1}_{1}p.

Double check the equation:

  • Sum of mass number on the left-hand side = 203 = 202 + 1 = Sum of mass number on the right-hand side.
  • Sum of atomic number on the left-hand side = 80 = 79 + 1 = Sum of atomic number on the right-hand side.

A gold-202 nucleus is formed.

6 0
3 years ago
What is the atomic mass of 3NaCl
givi [52]

Answer:

35.453

Explanation:

8 0
2 years ago
Explain whether nitrogen atoms will form bonds with other atoms
iren2701 [21]
The closer the atoms are the more the nitrogen will be come bigger or the oppisite

3 0
3 years ago
An original sample of the radioisotope fluorine-21 had a mass of 80.0 milligrams. Only 20.0 milligrams of this original sample r
lyudmila [28]

<u>Answer:</u> The correct answer is Option 3.

<u>Explanation:</u>

All the radioisotope decay processes follow first order kinetics.

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,  

k = rate constant  = ?

t = time taken for decay process = 8.32 seconds

a = initial amount of the reactant  = 80 mg

a - x = amount left after decay process  = 20 mg

Putting values in above equation, we get:

k=\frac{2.303}{8.32sec}\log\frac{80g}{20}\\\\k=0.166sec^{-1}

The equation used to calculate half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life of the reaction = ?

k = 0.166sec^{-1}

Putting values in above equation, we get:

t_{1/2}=\frac{0.693}{0.166sec^{-1}}=4.16sec

Hence, the correct answer is Option 3.

5 0
3 years ago
Read 2 more answers
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