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lys-0071 [83]
3 years ago
7

A person weighing 55 kg walks by applying 160 N of force on the ground, while pushing a 10-kg object. If the person accelerates

at 2 m/s2, what is the force of friction experienced by the system consisting of the person and the object?
Physics
1 answer:
lozanna [386]3 years ago
6 0

Answer:

idk

Explanation:

since i didn't answer it right, keep up with my questions and u can answer it with idk for 100 brainly points.

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A 500 kg rollercoaster car starts from rest at the top of a 10.0 m tall hill. it then travels down the track and up a loop. the
malfutka [58]

Speed of the roller coaster at the top of the loop= 7.67 m/s

Explanation:

using the law of conservation of energy

KEi + PEi= KEf + PEf

KEi= kinetic energy at the top of the hill=0 because the car is at rest there.

PEi= potential energy at the top of the hill

PEf= potential energy at the top of the loop

KEf= kinetic energy at the top of the loop

Also kinetic energy= 1/ 2m v² and potential energy= mgh

m= mass

h= height

v= velocity

so 0+ mghi = 1/2mv² + mg h

500 (9.8)(10)+ 1/2 (500) v²= 500 ( 9.8) (7)

49000+250 v²= 34300

250v²= 14700

v²=58.8

v=7.67 m/s

4 0
3 years ago
Why is the moons surface much more heavily cratered than earths surface
wlad13 [49]
The earth has less creators because there is a protective atmosphere which makes the asteroids burn up before they hit the surface of earth. Which means by the moon not having an atmosphere small rocks are easily colliding with the moons surface.
4 0
3 years ago
Which of the following are considered to be a form of clastic sedimentary rock?
umka21 [38]

Answer:

the answer to the question is c

3 0
3 years ago
Read 2 more answers
Plz help fast!!
barxatty [35]
We are asked to compare two series circuits having equal number of light bulbs.
1st circuit is powered by 6 batteries each having a voltage of 1.5V
2nd circuit is powered by a single battery having a voltage of 9V.
The six batteries in the 1st circuit can be connected together in series or in parallel.
When the batteries are connected in series (positive terminal of one battery connected to negative terminal of another battery) their voltage gets added which means
Voltage of pack = number of batteries*voltage of each battery
Voltage of pack = 6*1.5
Voltage of pack = 9 volts
But the current remains same in the series connection since there is only path for the current to flow.
On the other hand, when the batteries are connected in parallel, the voltage remains same but the current increases.
Circuit 1:
In this circuit, we have 6 batteries each of 1.5 volts connected in series to provide a voltage of 9 volts.
We have connected 2 bulbs in this series circuit.
The voltage will be equally divided between two bulbs if both bulbs are identical in construction.
So there will be 4.5 volts across each bulb and both bulbs will have same brightness.
Circuit 2:
In this circuit, we have 1 battery which provide a voltage of 9 volts.
We have connected 2 bulbs in this series circuit just like in circuit 1.
The voltage will be equally divided between two bulbs if both bulbs are identical in construction.
So there will be 4.5 volts across each bulb and both bulbs will have same brightness.
Conclusion:
Both series circuits provide a total voltage of 9 volts to the two bulbs connected in series and the voltage will be equally divided among two bulbs and they will have same brightness. Therefore, both circuits will have same characteristics.
5 0
4 years ago
B.
aniked [119]

Answer:

Kinematics of the parabolic movement

To solve the problem we will apply the kinematic equations of linear motion, which are an essential part in the characterization of parabolic motion. In this case we require the definition of acceleration described mathematically as,

a

=

v

f

−

v

i

t

Here,

v

f

=

Final Velocity

v

i

=

Initial Velocity

t

=

Time

Answer and Explanation: 1

Become a Study.com member to unlock this answer! Create your account

According to the information provided we have to

{eq}\text{Initial Velocity} = v_i = 4.0\text{ m/s}\\ \text{Initial Velocity} = v_f = 0.80\text{

6 0
2 years ago
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