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egoroff_w [7]
2 years ago
7

The main mast of s sailboat is supported by a rope that extends from the top of the mast to the deck. If the mast is 23 feet tal

l and the rope attaches to the deck 15 feet away from the base of the mast, how long is the rope? ​

Mathematics
1 answer:
WINSTONCH [101]2 years ago
8 0

Answer:

27.46

Step-by-step explanation:

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Round 74952 to the nearest 1000
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75,000 is the answer!

If this was the appropiate answer make sure to mark as the brainliest!
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Sam wanted to buy candy for all of his friends to share at lunch. One pound of chocolates cost $6.95, but Sim only needs 0.6 of
OLga [1]

Answer:

The answer to your question is cost of 0.6 pound of candy $4.17

Step-by-step explanation:

Data

1 pound of candy = $6.95

only 0.6 pounds

final cost = ?

Process

1.- Use proportions to find the cost of 0.6 pounds of candy

               1 pound of candy -------------- $6.95

               0.6 pound of candy ----------   x

2.- Use cross multiplication

                 x = (0.6 x 6.95) / 1

3.- Simplification and result

                 x = $ 4.17          

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3 years ago
Tell how you could use a number line to determine which of two numbers is greater.
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You read a number line from left to right therefore numbers on the left are lesser than numbers on the right
3 0
3 years ago
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Luke and Matthew ran a lemonade stand on Saturday. They agreed that Matthew would get 60% of the profit because the lemonade sta
True [87]

Answer:

$15

Step-by-step explanation:

60/100*25=15

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State whether the following coordinates on a Cartesian plane form an acute, obtuse or right triangle: a) (-1, 1), (7,-2) and (1,
LiRa [457]

Answer:

a) Acute triangle

b) Right triangle

Step-by-step explanation:

∵ A triangle having sides a, b and c is called,

Acute : If a² + b² > c² or a² + c² > b² or b² + c² > a²,

Obtuse : if a² + b² < c² or a² + c² < b² or b² + c² < a²

Right : a² + b² = c² or a² + c² = b² or b² + c² = a²,

a) Let A≡(-1, 1), B≡(7,-2) and C≡(1,-5),

By the distance formula,

AB=\sqrt{(7-(-1))^2+(-2-1)^2}=\sqrt{(7+1)^2+(-3)^2}=\sqrt{8^2+3^2}=\sqrt{64+9}=\sqrt{73}\text{ unit}

Similarly,

BC=\sqrt{45}\text{ unit}

CA=\sqrt{40}\text{ unit}

∵ The sum of any two sides is greater than third side,

So, ABC is a triangle,

Now,

AB^2 + BC^2 > CA^2

⇒ ABC is an acute triangle.

b) Let P≡(0,6), Q≡(1,2) and R≡(5,3),

By the distance formula,

PQ = √17 unit,

QR = √17 unit,

RP = √34 unit,

∵ The sum of any two sides of PQR is greater than third side,

⇒ PQR is a triangle ,

Also,

RP^2=PQ^2+QR^2

Hence, PQR is a right triangle.

3 0
3 years ago
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