The process that produces the energy radiated by stars is nuclear fusion in the core.
For a star on the main sequence, it's the fusion of hydrogen nuclei into helium.
Answer:
None
Explanation:
Subatomic particles are the particles which are very smaller than the atoms. Elementary particles are the examples of subatomic particles.
Elementary particles are the particles without any sub-structure which means they are not composed of other particles.
The elementary particles are classified into three categories which are discussed below:
(1) Quarks: up, down, top, bottom, strange, and charm.
(2) Leptons: muon, muon neutrino, electrons, electron neutrino, tau, tau neutrino.
(3) Bosons: Z bosons, W bosons, Higgs, Gluon, photons.
Mesons are the particles which compose one quark and one anti quarks.
Therefore, in the given list there is no meson.
The refractive index of water is

. This means that the speed of the light in the water is:

The relationship between frequency f and wavelength

of a wave is given by:

where v is the speed of the wave in the medium. The frequency of the light does not change when it moves from one medium to the other one, so we can compute the ratio between the wavelength of the light in water

to that in air

as

where v is the speed of light in water and c is the speed of light in air. Re-arranging this formula and by using

, we find

which is the wavelength of light in water.
Answer:
False
Explanation:
The net force is equal to the applied force minus the force of friction. It is possible for friction to act in the same direction as an applied force, but that would mean there would have to be more than two forces acting on the object.
Answer:
The right solution is "165.8 nm".
Explanation:
Given:
Index of refraction,
n = 1.81
Wavelength,
λ = 600 nm
We know that,
⇒ 
By putting the values, we get

