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Alik [6]
3 years ago
14

REEEEEEEEEEEEEEEEEE​

Physics
1 answer:
SpyIntel [72]3 years ago
4 0

Answer:

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What are hot clouds of gaseous elements and compounds that act as nurseries for stars
Aleks04 [339]
Interstellar gas clouds are common in many galaxy, like the Orion nebulae which many young stars are being born. A typical nebula is many light years in diameter and contains enough material mass to make several thousand stars the size of our sun. The majority of the gas in nebulae consist of molecules of hydrogen and helium-but most nebulae also contain atoms of other elements. All known element in our periodic table is also being made inside this crucible of this immense hot gas. The source of the organic molecules is still a mystery. Irregularities in the density of the gas causes a net gravitational force that pull the gas molecules close together.
3 0
3 years ago
A ping-pong ball is shot straight north from a popgun at 4.0 m/s. The wind is blowing to the west at 3.0 m/s. What is the actual
Vlad1618 [11]

Actual velocity of the ping-pong ball= 5 m/s

Explanation:

velocity of ping pong ball because of the shot gun= 4 m/s North

velocity added to the ping-pong ball due to the wind=3 m/s

These velocities are perpendicular to each other. so we use Pythagoras theorem to find the resultant velocity of the ping- pong ball

so the actual velocity of the ping-pong ball =V= √4²+3²

V= √25

V= 5 m/s

5 0
4 years ago
A planet similar to the Earth has a radius 7.4 × 106 m and has an acceleration of gravity of 10 m/s 2 on the planet’s surface. T
Lubov Fominskaja [6]

Answer:

1.5 hr

16.7

Explanation:

Zero apparent weight means there's no normal force.

Sum the forces in the centripetal direction.

∑F = ma

mg = mv²/r

v = √(gr)

v = √(7.4×10⁶ m × 10 m/s²)

v = 8602 m/s

The circumference of the equator is:

C = 2πr

C = 2π (7.4×10⁶ m)

C = 4.65×10⁷ m

So the period is:

T = C / v

T = (4.65×10⁷ m) / (8602 m/s)

T = 5405 s

T = 1.5 hr

The initial speed is:

v = C / T

v = (4.65×10⁷ m) / (25 h × 3600 s/h)

v = 517 m/s

The speed increases by a factor of:

8602 m/s / 517 m/s

16.7

3 0
3 years ago
A 0.0140 kg bullet traveling at 205 m/s east hits a motionless 1.80 kg block and bounces off it, retracing its original path wit
makvit [3.9K]

Answer:

Final velocity of the block = 2.40 m/s east.

Explanation:

Here momentum is conserved.

Initial momentum = Final momentum

Mass of bullet = 0.0140 kg

Consider east as positive.

Initial velocity of bullet = 205 m/s

Mass of Block = 1.8 kg

Initial velocity of block = 0 m/s

Initial momentum = 0.014 x 205 + 1.8 x 0 = 2.87 kg m/s

Final velocity of bullet = -103 m/s

We need to find final velocity of the block( u )

Final momentum = 0.014 x -103+ 1.8 x u = -1.442 + 1.8 u

We have

            2.87 = -1.442 + 1.8 u

               u = 2.40 m/s

Final velocity of the block = 2.40 m/s east.

7 0
4 years ago
This is my question ​
aliya0001 [1]

Answer: left and applied force

Explanation:

5 0
3 years ago
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