Is this true or false? the answer is false
Answer:
4.52 grams of potassium chloride
Explanation:
First you need a balanced reaction equation K(s) + Cl₂ (g) --> 2 KCl(s). Since the chlorine gas is said to be in excess all of the potassium will be converted to form potassium chloride. Convert grams of potassium to moles of potassium with the periodic table, then you can convert moles of potassium to moles of potassium chloride with the balanced equation, finally convert moles of potassium chloride to grams of potassium chloride with the periodic table. Set up a dimensional analysis chart to help with conversions
(2.50 grams K) * (<u>1 mole K</u>) * (<u>2 mole KCl)</u> * (<u>35.45 grams KCl</u>)
(39.09 grams K) (1 mole K) (1 mol KCl)
Which equals 4.52440778 grams, with sig figs it should be 4.52 grams of potassium chloride
Answer:
mL sugar sold needed = 2.2215 mL sugar
Explanation:
mass sugar = 7.57 g
∴ wt% = 5% = (g sugar/g sln)×100
⇒ 0.05 = g sugar/g sln
∴ g sln = 100 g
⇒ g sugar = 5 g
∴ δ sugar = 1.157 g/mL
⇒ mL sugar = (5 g)×(mL/1.157 g) = 4.322 mL
⇒ mL sugar needed = (7.57 g)/(1.157 g/mL) = 6.543 mL
mL of the sugar sold needed = 6.543 mL - 4.322 mL = 2.2215 mL sugar
1 kg -------------- 1000 g
x Kg ------------- 4251 g
1000 . x = 4251 . 1
1000 x = 4251
x = 4251 / 1000
x = 4.251 Kg
hope this helps !.
Answer:
- 1.602 x 10⁻¹⁹coulombs
Explanation:
Charge on individual oil droplet would be multiple of charge on one electron . So we will find out the minimum common factor of given individual charges that is the LCM of all the charges given.
LCM of given charges like 3.204 , 4.806 ,8.01 and 14.42 . We have neglected the power of ten( 10⁻¹⁹) because it is already a common factor to all.
The LCM is 1.602 . So charge on electron is 1.602 x 10⁻¹⁹.
