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julia-pushkina [17]
3 years ago
6

what sense can people use to detect infrared radiation? we can see it as red light, we can feel it as heat, we can hear it as a

loud noise, or we can smell it as fresh air
Physics
2 answers:
Ad libitum [116K]3 years ago
7 0
We can feel it as heat, using the nerve endings in our skins.

astraxan [27]3 years ago
6 0
We can feel it as heat!
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Use Coulomb’s law to derive the dimension for the permittivity of free space. <br><br><br><br>​
Paraphin [41]

Answer: M^-1 L^-3T^4A^2

Explanation:

From coloumb's law

K = q1q2 / (F × r^2)

Where;

q1, q2 = charges

k = constant (permittivity of free space)

r = distance

Charge (q) = current(A) × time(T) = TA

THEREFORE,

q1q2 = (TA) × (TA) = (TA)^2

Velocity = Distance(L) / time(T) = L/T

Acceleration = change in Velocity(L/T) / time (T)

Therefore, acceleration = LT^-2

Force(F) = Mass(M) × acceleration (LT^-2)

Force(F) = MLT^-2

Distance(r^2) = L^2

From ; K = q1q2 / (F × r^2)

K = (TA)^2 / (MLT^-2) (L^2)

K = T^2A^2M^-1L^-1T^2 L^-2

COLLEXTING LIKE TERMS

T^2+2 A^2 M^-1 L^-1-2

M^-1 L^-3T^4A^2

3 0
3 years ago
Long sand ridges oriented at right angles to the wind are called _____ dunes
S_A_V [24]

The answer is:

Transverse dune

The explanation:

Transverse dune : is abundant barchan dunes It  may merge into barchanoid ridges, which then grade into linear .

The transverse dunes is called that because they lie transverse, or across, the wind direction, with the wind blowing perpendicular to the ridge crest.

It is large, very asymmetrical, elongated dune lying at right angles 90° to the prevailing wind direction.

Transverse dunes have a gently sloping windward side and a steeply sloping leeward side.

They general form in areas of sparse vegetation and abundant sand are transverse dunes.

3 0
3 years ago
Read 2 more answers
What is the mass of a ball being rolled with a force of 200N at 3.5 m/s2?
aalyn [17]
F=ma (c) Newton, 2d Law
m=F/a=200/3.5=57kg
6 0
3 years ago
Calculate the change internal energy (δe) for a system that is giving off 45.0 kj of heat and is performing 855 j of work on th
adelina 88 [10]
The change in internal energy of a system is given by (second law of thermodynamics)
\Delta U = Q + W
where Q is the heat absorbed by the system and W is the work done on the system.

In order to correctly evaluate the internal energy change, we must be careful with the signs of Q and W:
Q positive -> Q absorbed by the system
Q negative -> Q released by the system
W positive -> W done on the system by the surroundings
W negative -> W done by the system on the surroundings

In our problem, the heat released by the system is Q=-45 kJ=-45000 J (with negative sign since it is released by the system), and the work done is W=-855 J still with negative sign because it is performed by the system on the surrounding, so the change in internal energy is
\Delta U = Q +W=-45000 J - 855 J=-45855 J
3 0
3 years ago
Cloudy nights are usually warm because​
almond37 [142]

Answer:

When you have a cloudy night, the clouds prevent heat from escaping through the atmosphere and into space.

The clouds act like a blanket and trap the heat it, and that is why every time you have a cloudy night, it is always warmer than a clear night.

5 0
3 years ago
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