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nekit [7.7K]
3 years ago
12

An object glides on a horizontal tabletop with a coefficient of kinetic friction of 0.5. If its initial velocity is 4.3 m/s, how

long does it take for the object to come to rest
Physics
1 answer:
Shkiper50 [21]3 years ago
8 0

Answer:

Time, t = 0.87 seconds

Explanation:

Given that,

Initial velocity of the object, u = 4.3 m/s

The coefficient of kinetic friction between horizontal tabletop and the object is 0.5

We need to find the time taken by the object for the object to come to rest i.e. final velocity will be 0.

Using first equation of motion to find it as :

v=u+at

a is the acceleration, here, a=\mu g

0=u+\mu gt

t=\dfrac{u}{\mu g}\\\\t=\dfrac{4.3}{0.5\times 9.8}\\\\t=0.87\ s

So, the time taken by the object to come at rest is 0.87 seconds. Hence, this is the required solution.

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Answer:

EL SONIDO PUEDE VIAJAR POR CUALQUIER MEDIO MATERIAL, COMO

AIRE, NITRÓGENO, AGUA, TITANIO, ETC...  ASÍ QUE EL

SONIDO VIAJA A TRAVÉS DE MOLÉCULAS.

Explanation:

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3 years ago
DC current is flowing in the primary coil of a transformer. Which of the following DOES NOT happen? A. There is a magnetic field
GrogVix [38]

Answer:

d

Explanation:

and just because trust me on this one my guy

7 0
3 years ago
Read 2 more answers
A 7.00-kg object accelerates from rest to a final velocity in 55 seconds. If the magnitude of the
Len [333]

Answer:

The final velocity of the object is 330 m/s.

Explanation:

To solve this problem, we first must find the acceleration of the object.  We can do this using Newton's Second Law, given by the following equation:

F = ma

If we plug in the values that we are given in the problem, we get:

42 = 7 (a)

To solve for a, we simply divide both sides of the equation by 7.

42/7 = 7a/7

a = 6 m/s^2

Next, we should write out all of the information we have and what we are looking for.

a = 6 m/s^2

v1 = 0 m/s

t  = 55 s

v2 = ?

We can use a kinematic equation to solve this problem.  We should use:

v2 = v1 + at

If we plug in the values listed above, we should get:

v2 = 0 + (6)(55)

Next, we should solve the problem by performing the multiplication on the right side of the equation.

v2 = 330 m/s

Therefore, the final velocity reached by the object is 330 m/s.

Hope this helps!

7 0
3 years ago
Calculate the momentum of of a 1,5000 kg car traveling at 6 m/s
ANEK [815]

Answer: 90000 kgm/s

Explanation:

Given that,

Momentum of car = ?

Mass of car = 1,5000 kg

Velocity of car = 6 m/s

Recall that momentum is the product of mass of the moving object by its velocity

i.e Momentum = mass x velocity

Momentum = 15000kg x 6m/s

= 90000kgm/s

Thus, the momentum of the car is 90000 kgm/s

4 0
4 years ago
Given that the CFL bulb is rated at 10% efficiency, if the LED bulb consumes half the amount of electrical power, for the same a
Butoxors [25]

Answer and explanation:

The efficiency of the LED bulb is 20% while The efficiency of the Inc bulb is 1%.

The lightbulb efficiency can be defined as the quotient between the amount of usable light and the amount of electrical power output. For the efficiency of the CFL Bulb:

\epsilon_{CFL}=\frac{L_0}{P_0}=0.1

Therefore:

\epsilon_{led}=\frac{L_0}{0.5P_0}=2 \cdot0.1=0.2\\\epsilon_{INC}=\frac{L_0}{10P_0}=0.1 \cdot 0.1=0.01

4 0
3 years ago
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