Answer:
The molarity of the solution is 0.048 M (option B)
Explanation:
<u>Step 1: </u>Data given
Sucralfate has a molar mass of 2087 g/mole
mass = 1g
volume = 10 mL
<u>Step 2: </u> Calculate moles of sucralfate
Number of moles = mass of sucralfate / Molar mass of sucralfate
Number of moles = 1 g / 2087 g/mole = 4.79 * 10^-4 moles
<u>Step 3:</u> Calculate molarity
Molarity = Number of moles / volume
Molarity = (4.79 * 10^-4 moles) / (10 *10^-3 L)
Molarity = 0.0479 M ≈ 0.048 M
The molarity of the solution is 0.048 M (option B)
Answer: The molar concentration of oxygen gas in water is
.
Explanation:
Partial pressure of the
gas = 685 torr = 0.8905 bar
1 torr = 0.0013 bar
According Henry's law:

Value of Henry's constant of oxygen gas at 20 °C in water = 34860 bar


Let the number of moles of
gas in 1 liter water be n.
1 Liter water = 1000 g of water
Moles of water in 1 L 




Molar concentration of oxygen gas in 1 L of water:

The molar concentration of oxygen gas in water is
.
In an electrochemical cell in which the oxidation reaction is nonspontaneous the oxidation will not occur spontaneously at the anode and the reduction will not be spontaneous at the cathode. And according to the law for the calculation of the voltage potential of the electrochemical cell (Ecell):
Ecell = Eox. - Ere. where (Eox. is the potential of the oxidation at the anode and Ere. is the potential of the reduction at the cathode). The standard potential for an electrolytic cell is negative, because of the Ere. which is greater than Eox.
The answer is : less than zero.