Answer:
- The image will be located at -13 cm
- The height of image is 5.2 cm
Explanation:
First you should remember that the images produced by convex mirror is virtual.
In this question, you should find the focal length using the radius of curvature, then apply the focal length relationship to find the image distance which is a virtual distance and finally use the magnification relationship to find the image height.
Let;
- height of object=h
- distance of object from mirror=o
- radius of curvature=r
- image distance=i
- height of image=h'
- focal length=f
<u>Find the focal length</u>
f=focal length is half the radius of curvature
f=r/2=34/2 =17cm =0.17m (This distance is virtual thus include a -ve sign)
f= -0.17m
<u>Apply the focal length relationship</u>
Solve for the reciprocal
This is a virtual distance for the virtual image formed
<u>Apply the magnification relationship</u>
Magnification = height of image÷height of object
or
Magnification= - image distance÷object distance
Accelerating at 9.8 m/s² means that every second, the speed is 9.8 m/s faster than it was a second earlier. It's not important to the problem, but this number (9.8) happens to be the acceleration of gravity on Earth.
1% of the speed of light = (300,000,000 m/s) / 100 = 3,000,000 m/s .
Starting from zero speed, moving (9.8 m/s) faster every second,
how long does it take to reach 3,000,000 m/s ?
(3,000,000 m/s) / (9.8 m/s²) = 306,122 seconds .
(That's 5,102 minutes.)
(That's 85 hours.)
(That's 3.54 days.)
Speed at the beginning . . . zero .
Speed at the end . . . 3,000,000 m/s
Average speed . . . . . 1,500,000 m/s
Distance = (average speed) x (time)
= (1,500,000 m/s) x (306,122 sec) = 4.592 x 10¹¹ meters
= 459 million kilometers
That's like from Earth
to Sun
to Earth
to Sun.
Answer:
Explanation:
We are given that
Mass of uranium,
Initial velocity,u=0
Mass of helium nucleus,
Mass of thorium,
Speed of helium nucleus,
We have to find the speed of the thorium nucleus.
According to law of conservation of momentum
Initial momentum=Final momentum
The simple answer would be; closeness to the equator combined with general climate.
This depends on what units you need to convert to, but the answer would be approximately 2.083 m/s.
5km/40min = 5000m/40min = 5000m/2400s = 2.083 m/s