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2 years ago

Most of the water on Earth is

Physics

2 answers:

e-lub [12.9K]2 years ago

7 0

Answer:

3% of the earth's water is fresh. 2.5% of the earth's fresh water is unavailable: locked up in glaciers, polar ice caps, atmosphere, and soil; highly polluted; or lies too far under the earth's surface to be extracted at an affordable cost. 0.5% of the earth's water is available fresh water.

To break the numbers down, 96.5% of all the Earth's water is contained within the oceans as salt water, while the remaining 3.5% is freshwater lakes and frozen water locked up in glaciers and the polar ice caps. Of that fresh water, almost all of it takes the form of ice: 69% of it, to be exact.

As these charts and the data table show, the amount of water locked up in ice and snow is only about 1.7 percent of all water on Earth, but the majority of total freshwater on Earth, about 68.7 percent, is held in ice caps and glaciers. Source: Gleick, P. H., 1996: Water resources.

The earth has an abundance of water, but unfortunately, only a small percentage (about 0.3 percent), is even usable by humans. The other 99.7 percent is in the oceans, soils, icecaps, and floating in the atmosphere. Still, much of the 0.3 percent that is useable is unattainable.

Explanation:

I hope this answer help you.

Serga [27]2 years ago

5 0

I think it’s either c or a

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The equation for the speed of a satellite in a circular orbit around the earth depends on mass. Which mass?

katovenus [111]

<h3><u>Question: </u></h3>

The equation for the speed of a satellite in a circular orbit around the Earth depends on mass. Which mass?

a. The mass of the sun

b. The mass of the satellite

c. The mass of the Earth

<h3><u>Answer:</u></h3>

The equation for the speed of a satellite orbiting in a circular path around the earth depends upon the mass of Earth.

Option c

<h3><u> Explanation: </u></h3>

Any particular body performing circular motion has a centripetal force in picture. In this case of a satellite revolving in a circular orbit around the earth, the necessary centripetal force is provided by the gravitational force between the satellite and earth. Hence $F_{G} = F_{C}$ .

Gravitational force between Earth and Satellite: $F_{G} = \frac{G \times M_e \times M_s}{R^2}$

Centripetal force of Satellite : $F_C = \frac{M_s \times V^2}{R}$

Where G = Gravitational Constant

$M_e$ = Mass of Earth

$M_s$ = Mass of satellite

R= Radius of satellite’s circular orbit

V = Speed of satellite

Equating $F_G = F_C$ , we get

Speed of Satellite $V =\frac{\sqrt{G \times M_e}}{R}$

Thus the speed of satellite depends only on the mass of Earth.

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3 years ago

What is the smallest accurate measurement that can be made with an instrument?

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Dependent on what you are measuring and what took you are using. Please be more specific.

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3 years ago

Words that describe direction east, up, and left is it true or false

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Explanation:

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3 years ago

an electron, a proton and a deuteron move in a magnetic field with same momentum perpendicularly. the ratio of the radii of thei

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If an electron, a proton, and a deuteron move in a magnetic field with the same momentum perpendicularly, the ratio of the radii of their circular paths will be:

1: √2 : 1

<h3>How is the ratio of the perpendicular parts obtained?</h3>

To obtain the ratio of the perpendicular parts, one begins bdy noting that the mass of the proton = 1m, the mass of deuteron = 2m, and the mass of the alpha particle = 4m.

The ratio of the radii of the parts can be obtained by finding the root of the masses and dividing this by the charge. When the coefficients are substituted into the formula, we will have:

r = √m/e : √2m/e : √4m/2e

When resolved, the resulting ratios will be:

1: √2 : 1

Learn more about the radii of their circular paths here:

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1 year ago

A 125-kg astronaut (including space suit) acquires a speed of 2.50 m/s by pushing off with her legs from a 1900-kg space capsule

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(a) 0.165 m/s

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$p_i = 0$

The final total momentum is instead:

$p_f = m_a v_a + m_c v_c$

where

$m_a = 125 kg$ is the mass of the astronaut

$v_a = 2.50 m/s$ is the velocity of the astronaut

$m_c = 1900 kg$ is the mass of the capsule

$v_c$ is the velocity of the capsule

Since the total momentum must be conserved, we have

$p_i = p_f = 0$

$m_a v_a + m_c v_c=0$

Solving the equation for $v_c$ , we find

$v_c = - \frac{m_a v_a}{m_c}=-\frac{(125 kg)(2.50 m/s)}{1900 kg}=-0.165 m/s$

(negative direction means opposite to the astronaut)

So, the change in speed of the capsule is 0.165 m/s.

(b) 520.8 N

We can calculate the average force exerted by the capsule on the man by using the impulse theorem, which states that the product between the average force and the time of the collision is equal to the change in momentum of the astronaut:

$F \Delta t = \Delta p$