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denis-greek [22]
3 years ago
13

Why does the static electricity in an object not constantly shock us?

Physics
1 answer:
Nina [5.8K]3 years ago
5 0

Answer:Static electricity is the result of an imbalance between negative and positive charges in an object. These charges can build up on the surface of an object until they find a way to be released or discharged.

Explanation:

hope this helped D:

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Calculate the average net force.
MrRa [10]

Answer:

<h2><u>given</u></h2>

<em>mass</em><em> </em><em>=</em><em> </em><em>39</em><em>5</em><em>0</em><em> </em><em>kg</em>

<em>speed</em><em>=</em><em> </em><em>2</em><em>5</em><em>m</em><em>/</em><em> </em><em>sec</em>

<em>time</em><em>=</em><em> </em><em>1</em><em>0</em><em>.</em><em>5</em><em> </em><em>sec</em>

<h2><em>To</em><em> </em><em>find</em><em> </em></h2>

<em>force</em><em> </em>

<h2><em><u>Solution</u></em></h2>

<h3><em>☄️</em><em>Formula</em><em> </em><em>of</em><em> </em><em>force</em><em> </em></h3>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<em>\fbox{f = m.a}</em>

<u><em>To</em><em> </em><em>find</em><em> </em><em>the </em><em>force </em><em>we</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>the </em><em>Acceleration</em><em> </em><em>first</em><em>.</em></u>

<em>accler</em><em>ation</em><em>=</em><em> </em><em>change</em><em> </em><em>in</em><em> </em><em>Velocity</em><em>/</em><em>time</em>

<em>accle</em><em>ration</em><em>=</em><em> </em><em>2</em><em>5</em><em>/</em><em>1</em><em>0</em><em>.</em><em>5</em>

<u><em>acc</em><em>leration</em><em>=</em><em> </em><em>2.38</em><em> </em><em>m</em><em>/</em><em>sec²</em></u>

<u><em>put</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>accle</em><em>ration</em><em> </em><em>in</em><em> </em><em>the </em><em>formula</em><em> of</em><em> force</em></u>

<u><em>force</em><em> </em><em>=</em><em> </em><em>Mass</em><em> </em><em>.</em><em> </em></u><em><u>accleration</u></em>

<em>force</em><em> </em><em>=</em><em> </em><em>39</em><em>5</em><em>0</em><em> </em><em>x</em><em> </em><em>2</em><em>.</em><em>3</em><em>8</em>

<h3><em>☄️</em><em>force</em><em> </em><em>=</em><em> </em><em>9,401</em><em> </em><em>Newton</em></h3>

3 0
3 years ago
A pharmacist works with a 1.75 m solution of sodium bromide (nabr) and water. the volume of the solution is 84.0 milliliters. if
Sav [38]

The volume of the diluted (i.e the new) solution given the data is 147 mL

<h3>Data obtained from the question </h3>
  • Molarity of stock solution (M₁) = 1.85 M
  • Volume of stock solution (V₁) = 84 mL
  • Molarity of diluted solution (M₂) = 1 M
  • Volume of diluted solution (V₂) = ?

<h3>How to determine the volume of diluted solution </h3>

M₁V₁ = M₂V₂

1.75 × 84 = 1 × V₂

V₂ = 147 mL

Thus, the volume of the new solution is 147 mL

Learn more about dilution:

brainly.com/question/15022582

#SPJ4

4 0
2 years ago
A girl with a mass of 27 kg is playing on a swing. There are three main forces
N76 [4]

The tension in the swing's chain at the bottom of the swing is 178.35 N.

The given parameters:

  • Mass of the girl, m = 27 kg
  • Speed of the girl, v = 3 m/s
  • Radius of the circle, r = 4 m

The tension in the swing's chain at the bottom of the swing is calculated as follows;

T = mg + ma_c\\\\ T= mg + \frac{mv^2}{r} \\\\T = (12 \times 9.8) + (\frac{27 \times 3^2}{4} )\\\\T = 117.6 \ N \ + \ 60.75 \ N\\\\T = 178.35 \ N

Thus, the tension in the swing's chain at the bottom of the swing is 178.35 N.

Learn more about tension in vertical circle here: brainly.com/question/19904705

3 0
2 years ago
Difference betwwen Acclerat<br>ion and retradation​
BartSMP [9]
I’m pretty sure one increases just straight up velocity and the other is kind of a deceleration
6 0
3 years ago
The equation T^2=A^3 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A
kobusy [5.1K]

Answer:

D. 2^(3/2)

Explanation:

Given that

T² = A³

Let the mean distance between the sun and planet Y be x

Therefore,

T(Y)² = x³

T(Y) = x^(3/2)

Let the mean distance between the sun and planet X be x/2

Therefore,

T(Y)² = (x/2)³

T(Y) = (x/2)^(3/2)

The factor of increase from planet X to planet Y is:

T(Y) / T(X) = x^(3/2) / (x/2)^(3/2)

T(Y) / T(X) = (2)^(3/2)

3 0
4 years ago
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