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ZanzabumX [31]
3 years ago
9

Write one to two sentences explaining whether this passage from the story is exposition, rising action, climax, or resolution: “

The announcer turned to point to the winner and found himself alone. Arm in arm the champions had already left the ring.”
Physics
2 answers:
hoa [83]3 years ago
7 0

Answer:

This sentence is half of the resolution the reason why is to she what later on in the climax. It puts the conflict together and the the end the story is done.

Explanation:

I just got the sample response and typed it in my own words :D

fiasKO [112]3 years ago
4 0

Answer:

This passage is part of the resolution because it shows what happens after the climax. It wraps up the conflict, and then the story is over.

Explanation: cause I am smart thats why

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erastovalidia [21]

To minimize neutron leakage from a reactor, the ratio of the surface area to the volume should be a minimum. For a given volume V the ratio of the sphere will be \frac{4.83598}{c^{\frac{1}{3} } }.

We know that the surface area and volume of the sphere is given by:

A=4 \pi r^{2}\\V=\frac{4}{3} \pi r^{3}

Therefore, the ratio between the surface area and the volume for the sphere will be:

\frac{A}{V}=\frac{4 \pi r^{2}\\}{\frac{4}{3} \pi r^{3}}=\frac{3}{r}

Equating the volume to the constant c, we will find the value of r.

V=c=\frac{4}{3} \pi r^{3}\\r= (\frac{3c}{4\pi} )^{\frac{1}{3} }

Substituting the value of r in the ration between surface area and volume, we get:

\frac{A}{V}=\frac{3}{ (\frac{3c}{4\pi} )^{\frac{1}{3} }}

Calculating the constants, we get:

\frac{4.83598}{c^{\frac{1}{3} } }

Hence, the ration between surface area and volume is \frac{4.83598}{c^{\frac{1}{3} } }

To learn more about surface area and volume of sphere, refer to:

brainly.com/question/4387241

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1 year ago
A series of optical telescopes produced an image that has a resolution of about 0.00350 arc second.
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Answer:

The smallest diameter is D =122 \ m

Explanation:

From the question we are told that

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From the question we are told that

        1 arc \ sec = \frac{1}{3600^o}

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   So  (9.722*10^{-7})^o =  \theta

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The smallest diameter is mathematically represented  as

          D = \frac{1.22 \lambda }{\theta  }

substituting values

           D = \frac{1.22 * 1.7 *10^{-6}} {1.69 *10^{-8}  }

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