That's what happens if there is more than one force acting on the
object, and the forces are balanced, that is, they all "cancel out".
Think of the rope in a Tug-'o-War. It has 50 musclebound football guys
all pulling the rope to the west, and 150 strong cheerleaders all pulling
the rope to the east. The total force to the west is exactly equal to the
total force to the east, and the rope doesn't move at all. The forces on it
are balanced, and the effect on its motion is the same as if there were
no force on it at all.
1.3s
Explanation:
Given parameters:
Height = 1.4m
Gravity on moon = 1.67ms⁻¹
Unknown:
Time for feather to fall = ?
Solution:
To solve this problem, we are going to use one of the motion equation that relates time, gravity and height.
H = ut + 
Sine the body was dropped from rest, initial velocity is zero;
H = height
u = initial velocity
t = time
g = acceleration due to gravity
since u = 0;
H = 
1.4 =
x 1.67 x t²
t = 1.3s
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Answer:
Calculate the total distance travelled by the object - its motion is represented by the velocity-time graph below.
Here, the distance travelled can be found by calculating the total area of the shaded sections below the line.
½ × base × height.
½ × 4 × 8 = 16 m 2
(10 – 4) × 8 = 48 m 2
Explanation:
In collision that are categorized as elastic, the total kinetic energy of the system is preserved such that,
KE1 = KE2
The kinetic energy of the system before the collision is solved below.
KE1 = (0.5)(25)(20)² + (0.5)(10g)(15)²
KE1 = 6125 g cm²/s²
This value should also be equal to KE2, which can be calculated using the conditions after the collision.
KE2 = 6125 g cm²/s² = (0.5)(10)(22.1)² + (0.5)(25)(x²)
The value of x from the equation is 17.16 cm/s.
Hence, the answer is 17.16 cm/s.