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3 years ago

Solve these.. . . . .

Chemistry

1 answer:

KonstantinChe [14]3 years ago

7 0

Answer:

Please find the ten balanced equations below

Explanation:

According to the question, a balanced equation must contain equal number of atoms on both sides of the equation. To balance an equation, coefficients are used. The following are the balanced equation:

1. C + O2 → CO2 (balanced)

2. 2H2 + O2 → 2H2O (balanced)

3. 2Na + 2H2O → 2NaOH + H2 (balanced)

4. 4Na + O2 → 2Na2O (balanced)

5. 2Na + Cl2 → 2NaCl (balanced)

6. NaOH + HCl → NaCl + H2O (balanced)

7. NaOH + HNO3 → NaNO3 + H2O (balanced)

8. 2NaOH + H2SO4 → Na2SO4 + 2H2O (balanced)

9. Na2CO3 + 2HCl → 2NaCl + H2O + CO2 (balanced)

10. 2NaOH + CO2 → Na2CO3 + H2O (balanced)

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How much heat energy in megajoules is neede to convert 7kilograms of ice at negative 9 degrees to water at 0 degrees celsius

den301095 [7]

Heat_1: Get the ice to 0 degrees

Convert 7 kg to grams

7 kg [1000 grams / 1 kg] = 7000 grams

Heat needed to get the the ice from - 9 to 0

deltat = 0 - -9 = 9 degrees

m = 7000 grams

c = 2.1 joules/gram

Heat_1 = m*c*deltat

Heat_1 = 7000 * 2.1 * 9

Heat_1 = 132,300 joules

Heat_2: Melt the ice.

There is no temperature change. The formula is 333 j/gram

Formula: H = mass * constant

H = 7000 g * 333 J / gram

H = 2331000 joules

Heat_3: Total amount of Joules needed.

2331000 + 132300 = 2 463 300 joules

Convert to Megajoules

2 463 300 joules * 1 megajoule / 1000000 = 2.63 megajoules.

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3 years ago

12.5 kilometers is equivalent to how many meters

storchak [24]

Hey! Thanks for submitting your question to brainly!

The answer is 12,500 meters

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Answer:

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3 years ago

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Dr. Patel and her team have been using GPS to track two plates that are moving toward each

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C: One plate is going underneath the other plate and sinking into the soft rock below.

Explanation:

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Plates have different motion. At some places, they move apart and they are said to be divergent.

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Learn more:

Lithosphere brainly.com/question/9582362

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3 years ago

Solve these.. . . . .​

Solve these.. . . . .