Solve these.. . . . .

Chemistry

1 answer:

KonstantinChe [14]3 years ago

7 0

Answer:

Please find the ten balanced equations below

Explanation:

According to the question, a balanced equation must contain equal number of atoms on both sides of the equation. To balance an equation, coefficients are used. The following are the balanced equation:

1. C + O2 → CO2 (balanced)

2. 2H2 + O2 → 2H2O (balanced)

3. 2Na + 2H2O → 2NaOH + H2 (balanced)

4. 4Na + O2 → 2Na2O (balanced)

5. 2Na + Cl2 → 2NaCl (balanced)

6. NaOH + HCl → NaCl + H2O (balanced)

7. NaOH + HNO3 → NaNO3 + H2O (balanced)

8. 2NaOH + H2SO4 → Na2SO4 + 2H2O (balanced)

9. Na2CO3 + 2HCl → 2NaCl + H2O + CO2 (balanced)

10. 2NaOH + CO2 → Na2CO3 + H2O (balanced)

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Answer:

2.8248 g

Explanation:

First, consider the balanced chemical equation:

$3NaHCO_{3} +C_{6}H_{8}O_{7} --->3CO_{2} +3H_{2}O +Na_{3}C_{6}H_{5}O_{7}\\$

Then we calculate the number of moles in 4.11 g of citric acid:

n(citric acid)= $\frac{4.11g}{192g/mol}=0.0214mol$

According to the balanced reaction, one mole of citric acid produces 3 moles of carbon dioxide. That's 3 times the number f moles of citric acid. So we will do the same with the available number of moles of citric acid.

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= 2.8248 g

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