Answer:
High concentration of glutathione should be included in the elution buffer for the given experiment to remove protein from the column.
Explanation:
Affinity chromatography is one of important biochemical technique of chromatography which depends on the affinity of ligand for the receptor.Here the ligand is a protein mixture which act as mobile phase and the receptor is present in the wall of chromatography column act as stationary phase.When the protein mixture is applied on the top of the column the substances present within the protein that have high affinity for the receptor present in the walls of chromatography column binds to the later but rest of the protein pass away through the column.High concentration of ligand is used within an buffer solution to remove the desired protein from the column.
From this point of view it can be stated that in the given question high concentration of glutathione should be used to remove the desired protein from the column.
Answer: B) The identity of the solvent
Explanation:
Basically, the solvent is the liquid in which a solute is dissolved in. But the solute is the material to be dissolved.
Now in this case, the solute in the first solution is glucose and the solute in the second solution is an unidentified covalent solid material.
This means that:
• the identity of the solute cannot be identical in each solutions, which also means that the freezing points and densities of the solutions cannot be identical too.
• the only thing that is sure to be identical in the solution is the identity of the solvent.
Answer:
1533.6 kg NO
Explanation:
The reaction that takes place is:
First we <u>convert the masses of ammonia (NH₃) and oxygen gas (O₂) into moles</u>, using<em> their respective molar masses</em>:
- NH₃ ⇒ 869 kg ÷ 17 kg/kmol = 51.12 kmol NH₃
- O₂ ⇒ 2480 kg ÷ 32 kg/kmol = 77.5 kmol O₂
77.5 kmol of O₂ would react completely with (77.5 kmol O₂ * ) 62 kmol of NH₃. There are not as many kmol of NH₃, so NH₃ is the limiting reactant.
Now we <u>calculate how many kmol of NO are produced</u>, using the <em>limiting reactant moles</em>:
- 51.12 kmol NH₃ * = 51.12 kmol NO
Finally we <u>convert kmol of NO to mass</u>, using its<em> molar mass</em>:
- 51.12 kmol NO * 30 kg/kmol = 1533.6 kg NO
Explanation:
tbh I really don't know but