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Naddik [55]
3 years ago
8

Using the periodic table, choose the more reactive nonmetal. Si or S

Chemistry
2 answers:
Setler [38]3 years ago
5 0
S is the more reactive nonmetal
larisa86 [58]3 years ago
4 0

s is the correct answer

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Abrasion is the answer
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Which answer choice is it?<br><br> A 3d<br><br> B 4p<br><br> C 4d<br><br> D 4f
Airida [17]

Answer:

3d

Explanation:

6 0
3 years ago
PLEASE HELP! How many grams of a stock solution that is 87.0 percent H2SO4 by mass would be needed to make 200 grams of a 35.5 p
icang [17]
Your answer will be m1= 8.609 grams
7 0
3 years ago
If 4.168 kJ of heat is added to a calorimeter containing 75.40 g of water, the temperature of the water and the calorimeter incr
Savatey [412]

Answer:

The value of  the heat capacity of the Calorimeter  C_c = 54.4 \frac{J}{c}

Explanation:

Given data

Heat added Q = 4.168 KJ = 4168 J

Mass of water m_w = 75.40 gm

Temperature change = ΔT = 35.82 - 24.58 = 11.24 ° c

From the given condition

Q = m_w C_w ΔT + C_c ΔT

Put all the values in above equation we get

4168 = 75.70 × 4.18 × 11.24 +  C_c × 11.24

611.37 =  C_c × 11.24

C_c = 54.4 \frac{J}{c}

This is the value of  the heat capacity of the Calorimeter.

5 0
3 years ago
When dinitrogen pentaoxide, a white solid, is heated, it decomposes to produce nitrogen dioxide gas and
AysviL [449]

9.5314 L is the volume of nitrogen dioxide formed at 103.25 kPa and 22.75 °C.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given data:

Oxygen produced - 1.618 gram

Decomposition of N_2O_5 takes place.

Find - Amount of NO_2 produced.

The decomposition reaction is as follows -

2N_2O_5--> 4NO_2 + O_2

Moles of O_2 gas =\frac{1.6}{16}  =0.1 moles.

1 mole of O_2 is produced from 2 moles of dinitrogen pentoxide

0.1 mole of O_2  will be produced from = 0.2 moles.

Now, 2 moles of dinitrogen pentoxide produce 4 moles of NO_2

NO_2 produced will be - 0.4 moles.

Weight of NO_2 produced - 0.4 X 46

Weight of NO_2  produced - 18.4 gram

Thus, grams of NO_2 produced are 18.4

Now calculate the volume of NO_2

Given data are:

P=103.25 kPa =1.01899827 atm

T= 22.75 °C +273 = 295.75 K

n=0.4 moles

V=?

R= 0.0821 liter·atm/mol·K

Putting the value in PV=nRT

V =  \frac{nRT}{P}

V =  \frac{0.4 \;moles \;X \;0.0821\; liter\;atm/\;mol \;K X \;295.75 \;K}{1.01899827 atm}

V= 9.5314 L

Hence, 9.5314 L is the volume of nitrogen dioxide formed at 103.25 kPa and 22.75 °C.

Learn more about the ideal gas equation here:

brainly.com/question/13450124

#SPJ1

8 0
2 years ago
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