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3 years ago

Spring tides have higher high tides and lower low tides when the moon, sun, and earth are aligned in a row. Why does this occur?

1 answer:

8 0

<span>Spring tides have higher high tides and lower low tides when the moon, sun, and earth are aligned in a row. Why does this occur?

A.gravitational pull is stronger
</span>

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How would you find the total energy stored in the

likoan [24]

Answer:

The energy of the capacitors connected in parallel is 0.27 J

Given:

C = $2.0\micro F = 2.0\times 10^{- 6} F$

C' = $4.0\micro F = 4.0\times 10^{- 6} F$

Potential difference, V = 300 V

Solution:

Now, we know that the equivalent capacitance of the two parallel connected capacitors is given by:

$C_{eq} = C + C' = 2.0 + 4.0 = 6.0\micro F = 6.0\times 10^{- 6} F$

The energy of the capacitor, E is given by;

$E = \frac{1}{2}C_{eq}V^{2}$

$E = \frac{1}{2}\times 6.0\times 10^{- 6}\times 300^{2} = 0.27 J$

6 0

2 years ago

URGENT!!! DUE AT 11:59, PLEASE DON’T POST A LINK FOR THIS ANSWER AND BE STRAIGHT FORWARD! Bronco the skydiver, whose mass is 100

kirill [66]

a = 7.8 m/s^2

Explanation:

Let Fnet = net force = ma

m = mass of the skydiver

a = acceleration caused by Fnet

W = weight = mg

f(air) = frictional force due to air resistance

Fnet = W - f(air)

= (100 kg)(9.8 m/s^2) - (200 N)

= 780 N

Therefore, the acceleration of the skydiver due to Fnet is

a = Fnet/m

= (780 N)/(100 kg)

= 7.8 m/s^2

4 0

2 years ago

Approximately where is it currently high tide on Earth? Group of answer choices wherever it is currently noon anywhere that ocea

Wewaii [24]

Answer:

Option D, only on the portion of the Earth facing directly toward the Moon

Explanation:

Tides are caused by the gravitational pull of moon. The part of earth that faces the moon experiences the highest gravitational force and hence the high tides will occur in this regions only. The regions that do not faces the moon experiences low tides. It is the gravity of moon that attracts the ocean water towards itself.

Hence, Option D is correct

7 0

2 years ago

A 180 g model airplane charged to 18 mC and traveling at 2.2 m/s passes within 8.6 cm of a wire, nearly parallel to its path, ca

viva [34]

Answer:

$a=0.2*10^{-5}g$

Explanation:

From the question we are told that:

Mass $M=180=>0.18kg$

Charge $Q=18mC=18*10^-^3C$

Velocity $v=2.2m/s$

Length of Wire $L=8.6cm=>0.086$

Current $I=30A$

Generally the equation for Magnetic Field of Wire B is mathematically given by

$B=\frac{\mu_0*I}{2\pi*l}$

$B=\frac{4*3.14*10^-^7*I}{2*3.14*8.6}$

$B=6.978*10^{-5}T$

Generally the equation for Force on the plane F is mathematically given by

$F=qvB$

Therefore

$ma=qvB$

$a=\frac{qvB}{m}$

$a=\frac{18*10^{-5}83.4*6.978*10^{-5}}{0.18kg}$

$a=2.37*10^{-5}$

Therefore in Terms of g's

$a=\frac{2.37*10^{-5}}{9.8}$

$a=0.2*10^{-5}g$

8 0

1 year ago

When you eat a candy bar, your body oxidizes glucose to get energy. where does this energy come from? kinetic energy of the gluc

babymother [125]

The correct answer is
<span>"chemical bonds within the glucose molecules "

The chemical bonds of the glucose molecules contain chemical energy, and when these bonds are broken by the processes acting inside the body, the energy of the bonds is released and it can be used by the body.

</span>

8 0

2 years ago