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masha68 [24]
3 years ago
11

What are five atomic models that have been proposed over time ?

Physics
1 answer:
Art [367]3 years ago
5 0
Air, water , atomic acid , and pocket rocket
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1)Pitch is measure of the ____________ of sound.
amid [387]

Answer:

1) wave length

2) parallel reflection

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2 years ago
Which is an example of reflection
Elena-2011 [213]

Common examples include the reflection of light, sound and water waves. The law of reflection says that for specular reflection the angle at which the wave is incident on the surface equals the angle at which it is reflected. Mirrors exhibit specular reflection.

5 0
3 years ago
An airplane is flying overhead at a constant elevation of 3000ft. A man is viewing the plane from a position 4000ft from the bas
ziro4ka [17]

Answer: The distance between the man and the plane increasing at a rate of 400ft/s

Explanation: Please see the attachments below

4 0
3 years ago
Three monkeys A, B, and C weighing 20, 26, and 25 lb, respectively, are climbing up and down the rope suspended from D. At the i
Marina86 [1]

Answer:2235.2lb-ft/s^2

Explanation:

Given

Mass of monkey A=20lb

Mass of monkey B=26lb

Mass of monkey C=25lb

acceleration of monkey A=4.2ft/s^2

acceleration of monkey B=0

acceleration of monkey C=-5.4ft/s^2

Force Due to monkey A\left ( F_A\right )=20\times 4.2 =84lb-ft/s^2\left ( downwards\right )

Force Due to monkey A\left ( F_B\right )=26\times 0 =0lb-ft/s^2

Force Due to monkey A\left ( F_C\right )=25\times 5.4 =135 lb-ft/s^2\left ( upward\right )

In addition to it  Weights of monkeys will be acting downwards therefore net Downwards force is balanced by tension

T=\left ( 20+26+25\right )32.2+84-135=2235.2 lb-ft/s^2

5 0
3 years ago
If an object is dropped from a height of meters, the velocity (in ) at impact is given by v= √2gh , where g=9.8m/sec^2 is the ac
Neporo4naja [7]

Answer:

A.) V = 14 m/s

B.) h = 36.6 m

Explanation:

Given the formula v = √2gh

where g = 9.8m/sec^2 is the acceleration due to gravity.

A.) Determine the impact velocity for an object dropped from a height of 10 m.

Substitute height h in the given formula

V = √2gh 

V = √2 × 9.8 × 10

V = √196

V = 14 m/s

b. Determine the height required for an object to have an impact velocity of 26.8 m/sec (~ 60 mph). Round to the nearest tenth of a meter.

Substitute the velocity in the given formula and make height h the subject of formula.

26.8 = √2 × 9.8 × h

Square both sides

718.24 = 19.6h

h = 718.24 / 19.6

h = 36.64 m

h = 36.6 m

5 0
3 years ago
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