Since the half-life is 4.5 billion years, two half-lives would have elapsed after 9 billion years.
<span>If you start with 400 g, half decays during the first half-life, leaving 200 g. </span>
<span>During the second half-life, half of the 200 g decays, leaving 100 g.</span>
Answer:
1. Vegetable oil, which is a liquid at room temperature, is used in making cake batter. <u>Unsaturated</u>
2. Chocolate, which is solid at room temperature, is derived from a seed. <u>Saturated</u>
3. Butter<u>,</u> which is a solid at room temperature, is often used in cooking. <u>Saturated</u>
4. The oil inside flaxseed oil pills is liquid at room temperature. <u>Unsaturated</u>
Explanation:
Saturated fats are those kinds of fat that do not have a double bond between their carbon atoms when represented structurally. At room temperature, they tend to assume the solid-state, and they are mostly obtained from animal sources. Unsaturated fats do have a minimum of one double bond between their carbon atoms and tend to assume the liquid phase. They are mostly obtained from plant sources.<em> </em>
1. Vegetable oil is obtained from a plant source and is, therefore, unsaturated fat.
2. Chocolate even though it comes from cocoa is solid at room temperature and is mostly comprised of saturated fat.
3. Butter a solid at room temperature is mostly made up of saturated fat and is sourced from animals.
4. Flaxseed oil obtained from a plant source is mostly unsaturated fat.
Spears and knives
(Plz thank me if this helped)
Answer: Apostrophes yes your right.
Explanation: An apostrophe is a punctuation mark (') that appears as part of a word to show possession, to make a plural number or to indicate the omission of one or more letters. Three Uses of Apostrophes: In most cases an apostrophe is used to show possession.
Answer:
1.47 atm
Explanation:
From the question.
Applying
PV = nRT................. Equation 1
Where P = pressure, V = volume, T = temperature, n = number of moles, R = Molar gas constant
Makr P the subject of the equation
P = nRT/V................ Euqation 2
Given: V = 50.0 L, n = 3.00 mol, T = 25°C = (273+25) = 298K,
Constant: R = 0.082 atm.L.K⁻¹mol⁻¹
Substitute these values into equation 2
P = (3×298×0.082)/(50)
P = 73.308/50
P = 1.46616
P ≈ 1.47 atm