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antoniya [11.8K]
2 years ago
7

Math question: I'm not good at math so pls help me

Mathematics
2 answers:
STALIN [3.7K]2 years ago
4 0

Answer: D: 1/14

Step-by-step explanation:

1/7 chance of picking orange marble, times 1/2 chance of flipping tails.

1/7 X 1/2 = 1/14

oksano4ka [1.4K]2 years ago
3 0

Answer:

c

Step-by-step explanation:

You might be interested in
A) Let f(x) = 4x + 2 and g(x) = 2x^2-4. Find the formula for the composition function gof
ollegr [7]

Answer:

g o f = g(f(x)) = 32x^2 + 32x + 4

Step-by-step explanation:

Given

f(x) = 4x +2

g(x) =2x^2 - 4

Required:

Find g o f

This is calculated as:

gof = g(f(x))

g(x) =2x^2 - 4

So:

g(f(x)) = 2(4x+2)^2 - 4

g(f(x)) = 2(4x+2)(4x+2) - 4

g(f(x)) = 2[ 16x^2 + 16x + 4)] - 4

g(f(x)) = 32x^2 + 32x + 8 - 4

g(f(x)) = 32x^2 + 32x + 4

5 0
3 years ago
Madisyn is planting crops in a triangular garden. She is trying to find the amount of fencing
MrRissso [65]

Answer:

Fencing needed = 20.8 units

Step-by-step explanation:

From the figure attached,

Given: Triangle ABC with vertices A(0, 6), B(6, 5) and C(5, -1).

We have to find the length of fence required to cover the triangular garden.

Amount of fencing required = Perimeter of the triangular garden

Perimeter of the garden = AB + BC + AC

Formula to get the distance between A and B,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AB = \sqrt{(0-6)^2+(6-5)^2} = \sqrt{37}

BC = \sqrt{(6-5)^2+(5+1)^2} = \sqrt{37}

AC = \sqrt{(0-5)^2+(6+1)^2} = \sqrt{74}

Perimeter = \sqrt{37}+\sqrt{37}+\sqrt{74}

                = 6.08 + 6.08 + 8.60

                = 20.76

                ≈ 20.8 units

Therefore, amount of fencing required to cover the triangular park is 20.8 units.

3 0
3 years ago
2 2/3 divided by 4 1/4​
viva [34]

Answer: your answer is 32/51

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Solve for the missing item in the following. (Do not round intermediate calculations. Round your answer to the nearest cent.)
iogann1982 [59]

9514 1404 393

Answer:

  $1904.76

Step-by-step explanation:

The interest formula is ...

  I = Prt . . . . interest on principal P at rate r for t years

Solving for P, we find ...

  P = I/(rt) = 200/(0.07·1.5) = 200/0.105 ≈ 1904.76

The principal amount was $1904.76.

7 0
2 years ago
La profesora de matemáticas solicita a dos estudiantes que describan las cosas que les han parecido interesantes de los números
Makovka662 [10]

Answer:

Respuesta D

Step-by-step explanation:

Paola afirma: Todo número compuesto par, se puede escribir como la multiplicación de factores primos.

Esta afirmación es cierta, pues es un caso  de la afirmación de que todo número natural mayor que uno se puede escribir como multiplicación de números primos. A este proceso se le llama descomposición en factores primos.

Edwin afirma: Todo número compuesto impar se puede escribir como la suma de dos números primos.

Esta afirmación es falsa. Note que al sumar dos números impares de la forma 2k+1 y 2m+1 para k distinto de m, se obtiene

2k+1+2m+1 = 2(km+1)

Es decir, la suma de dos números impares es siempre par.

Note que a excepción de 2, todo número primo es impar. Para que esta afirmación fuera cierta, necesariamente tendría que pasar que cualquier número impar k se escriba de la forma p+2 donde p es un número primo. Esto es equivalente que para cualquier número impar k, el número k-2 sea primo.

Basta con dar un ejemplo para ver que esto no pasa. Tomemos k=11. En este caso, k-2 = 9, el cuál no es un número primo. Entonces 11 no se puede  descomponer como la suma de dos números primos.

5 0
3 years ago
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