Answer:
0.78m (rounded to nearest hundredth of a meter)
explanation:
time taken for going up=time taken for drop down after reaching the highest point. at the highest point, the velocity becomes 0.
now all thats left is dropping an object from a height (h) and seeing how long it takes to reach the ground. then find out the flight’s total time divided by 2 (0.8/2=0.4)
lets say the velocity is v and the height she jumped to is h. we can make a kinematic expression:
s=vt+½gt²
once we put it all together you should get this:
h=0×0.4+½(9.81) 0.4²
.
∴
Time taken for downward drop
=
0.8
2
=
0.4
s
Suppose that she jumped with initial velocity
=
u
Also suppose that she jumped to a height
h
Using following kinematic expression
s
=
u
t
+
1
2
g
t
2
and inserting various quantities we get
h
=
0
×
0.4
+
1
2
(
9.81
)
0.4
2
h
=
0.78
m
rounded to nearest hundredth of a meter.
Explanation:
A paradigm can be defined as universally recognized scientific patterns theories or achievements that , for a time that provides a model for problems and solution for a community of practitioners. that is most accepted from of scientific ideas
(a). The power of the candy bar is,
The time taken to play on 800 kJ energy of the candy bar is,
where E is the energy.
Substituting the known values,
As 1 minute is equal to 60 seconds,
Thus,
Thus, the time taken to play tennis on the 800 kJ energy is 30.3 minutes.
(b). By doing the exercise, the process of digestion of food inside our body increases. Thus, the exercise does not helps us to burn the calories. But it helps us to diggest the heavy meal like candy bar easily.
The time taken to digest the canndy bar or to utilise its energy is large because it takes a lot of time to burn small amount of food and make it digest quickly.
Answer:
The maximum height is determined by the initial vertical velocity. Since steeper launch angles have a larger vertical velocity component, increasing the launch angle increases the maximum height.
Explanation:
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Answer:
Find the time it took for the car to stop at 11.0m/s
V = deltax/t
t = 41.14/11.0 = 3.74s
Now find at what rate it was decelerating, so find the acceleration during that interval of time.
vf = vi + at
-11.0m/s = a3.74s
a = -2.94m/s^2
The acceleration is negative because is pulling the car towards its opposite direction to make it stop.
Now find how much time it would take for the car to stop at 28.0m/s but with the same acceleration, the car is the same so its acceleration to stop the car will remain the same.
vf = vi + at
0 = 28.0 - 2.94t
t = 9.52
Once the time is obtained, you can find the final position, xf, by plugging the time acceleration and velocity values.
xf = 0 + (28m/s)(9.52s) + 1/2(-2.94)(9.52s)^2
xf = 266.6m - 133.23m = 133m
