The answer i think would be D
Answer:
Option 2 is the correct answer.
Explanation:
We have equation of motion s = ut + 0.5at²
Here u = 0 m/s
So, s = 0.5at²
Distance traveled in first second = 0.5 x a x 1² = 0.5 a
Distance traveled in second second = 0.5 x a x 2² - 0.5 x a x 1²= 1.5 a
Distance traveled in third second = 0.5 x a x 3² - 0.5 x a x 2²= 2.5 a
Distance traveled in fourth second = 0.5 x a x 4² - 0.5 x a x 3²= 3.5 a
The percentage increase in its displacement during the 4th second compared to its displacement in the 3rd second
Option 2 is the correct answer.
Answer: c. they will hit the ground at the same time
Explanation:
The volume of both objects is almost the same, so the force of friction will be the same in each one, so we can discard it.
Now, when yo drop an object, the acceleration of the object is always g = 9.8m/s^2 downwards, independent of the mass of the object.
So if you drop two objects with the same volume but different mass, because the acceleration is the same for both of them, they will hit the ground at the same time, this means that the density of the object has no impact in how much time the object needs to reach the floor.
So the correct option is c
Explanation:
PE = KE
mgh = ½ mv²
v = √(2gh)
v = √(2 × 9.8 m/s² × 0.75 m)
v = 3.83 m/s
Answer:
stopping potential is the negative potential applied to the circuit to stop the moving electrons so as to stop the flow of current
for high current high negative potential is applied