Three different units of energy is
1. Joule: is is SI unit of measuring thermal energy or heat
2. Calorie: this system of energy is used when we take CGS system of mass and specific heat capacity
3. BTU: this system is known as british thermal unit which is used in measuring engineering calculations
Answer:
the orbit radius would be divided by 3
Explanation:
In order to orbit the planet, the centripetal force of satellite must balance the gravitational force between planet and satellite.
centripetal Force = Gravitational Force
(Ms)(V)²/r = (G)(Ms)(Mₓ)/r²
V² = GMₓ/r
where,
V = velocity of satellite
G = Gravitational Constant
Mₓ = Mass of Planet
r = orbit radius
but, G = gr²/Mₓ
Therefore,
V² = (Mₓ/r)(gr²/Mₓ)
V = √gr --------------------- equation (1)
where,
g = force of gravity
Now, for change in force of gravity:
V' = √g'r'
where,
g' = 3g
V' = V
Therefore,
V = √3gr' ---------------- equation (2)
Comparing equation (1) and equation (2), we get:
√gr = √3gr'
gr = 3gr'
r = 3r'
r' = r/3
<u>Hence, the orbit radius would be divided by 3.</u>
Answer:
a) 
= 928 J
, b)U = -62.7 J
, c) K = 0
, d) Y = 11.0367 m, e) v = 15.23 m / s
Explanation:
To solve this exercise we will use the concepts of mechanical energy.
a) The elastic potential energy is
= ½ k x²
= ½ 2900 0.80²
= 928 J
b) place the origin at the point of the uncompressed spring, the spider's potential energy
U = m h and
U = 8 9.8 (-0.80)
U = -62.7 J
c) Before releasing the spring the spider is still, so its true speed and therefore the kinetic energy also
K = ½ m v²
K = 0
d) write the energy at two points, maximum compression and maximum height
Em₀ = ke = ½ m x²
= mg y
Emo =
½ k x² = m g y
y = ½ k x² / m g
y = ½ 2900 0.8² / (8 9.8)
y = 11.8367 m
As zero was placed for the spring without stretching the height from that reference is
Y = y- 0.80
Y = 11.8367 -0.80
Y = 11.0367 m
Bonus
Energy for maximum compression and uncompressed spring
Emo = ½ k x² = 928 J
= ½ m v²
Emo =
Emo = ½ m v²
v =√ 2Emo / m
v = √ (2 928/8)
v = 15.23 m / s
Assuming Earth's gravity, the formula for the flight of the particle is:
<span>s(t) = -16t^2 + vt + s = -16t^2 + 144t + 160. </span>
<span>This has a maximum when t = -b/(2a) = -144/[2(-16)] = -144/(-32) = 9/2. </span>
<span>Therefore, the maximum height is s(9/2) = -16(9/2)^2 + 144(9/2) + 160 = 484 feet. </span>
All three choices are correct.
