Left at 3 p.m
traveled 1 hr 30 min......now its 4:30 p.m.
stopped for 15 min....now its 4:45 p.m.
continued for 2 hrs 10 min....now its 6:55 p.m
so the train arrived at 6:55 p.m.
Answer:
use the quadruple double schlop schlop theorum
Step-by-step explanation:
Factor
25
out of
50
.
3
√
25
(
2
)
Rewrite
25
as
5
2
.
3
√
5
2
⋅
2
Pull terms out from under the radical.
3
(
5
√
2
)
Multiply
5
by
3
.
15
√
2
The result can be shown in multiple forms.
Exact Form:
15
√
2
Decimal Form:
21.21320343
Answer:
c
Step-by-step explanation:
The mean value theorem states that for a continuous and differentiable function on a interval there exists a number c from that interval, that
First we must determine the endpoints:
We find the derivative of the function, f'(c)
Therefore:
Simplify:
For this problem, you haven = 360p = 1/6q = 5/6 E[x] = np = 360*1/6 = 60SD[x] = √(npq) = √(360*1/6*5/6) = √(50) ≈ 7.07
There is one 8 in each intervals: 1-10, 11-20, 21-30, 31-40, 41-50, 51-60, 61-70, 71-79, 90-100, and ten numbers with 8 in 80-89.
from 1-100, there are a total of nineteen 8's.
So from 101-200, there will be nineteen as well. Same goes for 201-300.
so,
19*3=57
There are fifty seven number with 8 from 1 to 300
