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kogti [31]
3 years ago
9

Which of these describes a wave being reflected?

Chemistry
1 answer:
meriva3 years ago
3 0

Answer:

please don't waste people's time.

Explanation: I'd be glad to answer any question with proper details this one is unanswerable.

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Calculate the molar solubility of PbBr2 (Ksp = 4.67x10-6) in 0.10M NaBr solution.
Softa [21]

Explanation:

PbBr_{2} will dissociate into ions as follows.

         PbBr_{2}(s) \rightleftharpoons Pb^{2+}(aq) + 2Br^{-}(aq)

Hence, K_{sp} for this reaction will be as follows.

                   K_{sp} = [Pb^{2+}][Br^{-}]^{2}

We take x as the molar solubility of PbBr_{2} when we dissolve x moles of solution per liter.

Hence, ionic molarities in the saturated solution will be as follows.

               [Pb^{2+}] = [Pb^{2+}]_{o} + x

               [Br^{-}]^{2} = [Br^{-}]_{o} + 2x

So, equilibrium solubility expression will be as follows.

            K_{sp} = ([Pb^{2+}]_{o} + x)([Br^{-}]_{o} + 2x)^{2}

Each sodium bromide molecule is giving one bromide ion to the solution. Therefore, one solution contains [Br^{-}]_{o} = 0.10 and there will be no lead ions. So, [Pb^{2+}]_{o} = 0

So, [Br^{-}]_{o} + 2x will approximately equals to [Br^{-}]_{o}.

Hence, K_{sp} = x[Br^{-}]^{2}_{o}

            4.67 \times 10^{-6} = x \times (0.10)^{2}

                        x = 4.67 \times 10^{-4} M

Thus, we can conclude that molar solubility of PbBr_{2} is 4.67 \times 10^{-4} M.

5 0
3 years ago
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HELP!!!
vredina [299]

Answer:

the answer is A

Explanation:

I dont really have an explanation but hope it helps

5 0
2 years ago
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Why is the speed of these particles deffirent in each state
monitta

Answer:

due to difference ic kinetic energy

Explanation:

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2 years ago
Which statement correctly describes the ionization of acids?
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I have my biology notebook if that helps
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The constant k for a certain reaction is measured at two different temperatures:Temperature K376.0°C 4.8x 10^8280.0°C 2.3 x 10^8
zaharov [31]

Answer:

Explanation:

548888

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