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4 years ago

What is the volume of a flask containing 0.199mol of Cl2at a temperature of 313K and a pressure of 1.19atm

Chemistry

1 answer:

MrRissso [65]4 years ago

4 0

Answer:

43.0 L

Explanation:

Step 1: Given and required data

Moles of chlorine gas (n): 0.199 mol

Temperature (T): 313 K

Pressure (P): 1.19 atm

Ideal gas constant (R): 0.0821 atm.L/mol.K

Step 2: Calculate the volume of the flask (V)

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T / P

V = 1.99 mol × (0.0821 atm.L/mol.K) × 313 K / 1.19 atm = 43.0 L

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3 years ago

Hen the external pressure is 404 kPa, what is the vapor pressure of water at its boiling point?

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Consider the following equation: K + Br → KBr. How many grams of KBr can you make with 1.25g of K?

Dmitry [639]

Answer:

$\fbox{3.81 \: grams}$

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3 years ago

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Aleksandr [31]

Answer:

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3 years ago

Help plz:)))I’ll mark u Brainliest

emmasim [6.3K]

Answer:

$\Delta _{fus}H=205J/g=13.03kJ/mol$

Explanation:

Hello there!

In this case, since the heat of fusion is a property that allows us to calculate the heat involved during the change from solid to liquid (fusion) and is calculated as shown below:

$Q=m*\Delta _{fus}H$

In such a way, given the heat involved during this process and the mass of copper, we calculate the heat of fusion as shown below:

$\Delta _{fus}H=\frac{Q}{m}=\frac{41000J}{200.g}\\\\\Delta _{fus}H=205J/g$

Or in kJ/mol:

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3 years ago