Answer:
a) The gravitational acceleration at the surface of the Moon is g moon=1.67 m/s
2
The ratio of weights (for a given mass ) is the ratio of g-values, so
W
moon
=(100N)(1.67/9.8)=17N.
(b) For the force on that object caused by Earth's gravity to equal 17 N, then the free fall acceleration at its location must be
ag
=1.67m/s
2
. Thus , .
ag
= r 2
Gm
E
⇒
a
g
Gm
=1.5×10
7
m
So the object would need to be a distance of r/R
E
=2.4 "radii" from Earth's center.
Answer:
position 9.58 m
Explanation:
In impulse exercises and amount of movement, we always assume that the contact time is small,
I = Δp
With this expression we can calculate the final speed
I = m Vf - m Vo
Vf = (I + mVo) / m
Vf = (1.8 + 0.35 1.8) /0.35
Vf = 6.94 m / s
To calculate the acceleration of the ball we use Newton's second law, after finishing the impulse
∑ F = m a
fr = m a
a = fr / m
a = -0.26 / 0.35
a = -0.74 m/s²
A negative sign indicates that this acceleration is slowing the ball
Now we have speed and time acceleration, so we can use the kinematic equations to find the position at 1.5 s
X = Vo t + ½ to t²
In this case Vo is the speed with which the ball comes out after the impulse 6.94
X = 6.94 1.5 + ½ (-0.74) 1.522
X = 9.58 m
Answer: (E) Momentum and mechanical energy
Explanation:
The momentum and the mechanical energy is basically conserved during the given interaction process as the forces on the given system are in the form of internal nature and then the momentum are get conserved.
According to the given question, on the smooth floor when an object are slides by using the spring then the momentum and the mechanical energy are conserved.
The mechanical energy is the combination of both the kinetic and the potential energy that is used for doing some amount of work. Therefore, Option (E) is correct answer.
Answer:
d = 0.71 meters
Explanation:
It is given that,
Charge 1, 
Charge 2, 
Electrostatic force between charges, F = 9 N
Let d is the distance between the charges. The electrostatic force between the charges is given by the product of charges and divided by square of distance between them. Mathematically, it is given by :
d = 0.71 meters
So, the distance between the charges is 0.71 meters. Hence, this is the required solution.
