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Savatey [412]
3 years ago
11

Elements heavier than hydrogen are formed when light elements undergo nuclear fusion. Fusion takes place within stars at tempera

tures nearing 108K. Explain why this high energy is required for fusion to occur. A) High temperatures result in high kinetic energy that is converted to the nuclear binding energy. B) High temperatures result in the high kinetic energy needed to overcome the repulsive force of the two nuclei. C) High temperatures result in high kinetic energy that in turn creates a strong electrostatic force between the two nuclei. D) High temperatures result in the high kinetic energy needed to produce the strong force required to hold the nuclei together.
Physics
2 answers:
Gemiola [76]3 years ago
6 0

it would be B, Hight Temperatures result in the high kinetic energy needed to overcome the repulsive force of the two nuclei

LuckyWell [14K]3 years ago
3 0
B is the best answer.  Once the particles are sufficiently close, the strong nuclear force becomes stronger than the Coulomb repulsion and they are pulled together.  This results in bound particles that have a binding energy that can be retrieved of you can get the particles far enough away from one another after binding, but this requires large and unstable nuclei (beyond lead on the table)  These elements are referred to as radioactive, because they are prone to decaying
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Assuming this is a distance time graph( ignore the speed time title) assume metres on vertical scale. describe in as much detail
riadik2000 [5.3K]

Answer:

The journey started from point A, with a speed of  1 m/s for 10 seconds after which the it became stationary at 10 meters from the start point, for 10 seconds. The journey continued at a higher speed of 2 m/s for 5 seconds and halted (became stationary) again at 20 meters which was the maximum distance reached from the start point

The return journey to the start point started at the 20 meter mark and lasted for 5 seconds, at a speed of 4 m/s

The total distance travelled during the journey from the start point A to the final point B is 40 m

Explanation:

From the start point A to point B, we have;

The speed from A to B = 10 m/(10 s) = 1 m/s

The distance traveled from A to B = 10 m

The time it takes to move from A to B = 10 seconds

From the point B to point C, we have;

The distance traveled from B to C = 0 m, (stationary)

The time it remains at point B distance from the start point = 10 seconds

The speed between point B to C = 0 m/(10 s) = 0 m/s

From the point C to point D, we have;

The distance traveled from C to D = 10 m

The time it takes to move from C to D = 5 seconds

The speed between point C and D = 10 m/(5 s) = 2 m/s

From the point D to point E, we have;

The distance traveled from D to E = 0 m, (stationary)

The time it remains at point D distance from the start point = 10 seconds

The speed between point D to E = 0 m/(10 s) = 0 m/s

From the point E to point F, we have;

The distance traveled from E to F = 20 m (return journey starts at point E)

The time it takes to move from E to F = 5 seconds

The speed between point E to F = 20 m/(5 s) = 4 m/s (Return journey)

Therefore, the journey started from point A, with a speed of  1 m/s for 10 seconds after which the it became stationary at 10 meters from the start point, for 10 seconds. The journey continued at a higher speed of 2 m/s for 5 seconds and halted (became stationary) again at 20 meters which was the maximum distance reached from the start point

The return journey to the start point started at the 20 meter mark and lasted for 5 seconds, at a speed of 4 m/s

The total distance moved, 'd', to and from the start point with reference to the graph is given as follows;

d = (From A to B) 10 m + (From B to C) 0 m + (From C to D) 10 m + (From D to E) 0 m + (From E to F) 20 m = 40 m

The total distance travelled in the journey is 40 m

The total displacement, \underset{d}{\rightarrow} = 10 m + 10 m - 20 m = 0 m

7 0
3 years ago
A person who is good at caring for others might enjoy a career as a
julia-pushkina [17]
He or she would enjoying doing a job as a caretaker
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4 years ago
_______________ appears on the ecg as having no p wave, a wide qrs complex, and t waves that deflect in the opposite direction f
melomori [17]
It would probably be <span>Premature Ventricular Contractions.

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5 0
3 years ago
In this setup how can potential energy be converted into kinetic energy .
d1i1m1o1n [39]

Answer:

If force is applied to cause the motion of the body

Explanation:

In the setup given in this diagram, potential energy can be converted into kinetic energy by applying force on the cart or object to move it down the slope.

Potential energy is the energy due to the position of a body. The body has huge potential energy at its current position.

Kinetic energy is the energy due to the motion of a body.

As the body moves down the slope and its velocity increases, it gains massive kinetic energy.

Down the slope, the kinetic energy increases as the potential energy decreases.

At the bottom of the slope, the potential energy becomes zero and the kinetic energy is at its maximum.

7 0
3 years ago
(I) A 0.145-kg baseball pitched at 31.0 m/s is hit on a horizontal line drive straight back at the pitcher at 46.0 m/s. If the c
tangare [24]

Answer:

<em>The force between the ball and the bat = 2233 N</em>

Explanation:

Force: This can be defined as the product of force and its acceleration.

The S.I unit of Force is Newton (N)

F = ma .............................. Equation 1

Where F = Force , m = mass of the ball, a = acceleration of the ball.

where

a = (v-u)/t..................... Equation 2

Where v = final velocity of the ball, u = initial velocity of the ball, t = time of contact between the ball an the bat.

<em>Given: v = 46 m/s u = - 31 m/s (it hit an horizontal line drive back at the pitcher), t = 5×10⁻³ s</em>

<em>Substituting these values into equation 2,</em>

<em>a = [46-(31)]/(5×10⁻³ )</em>

a = 77<em>×10³/5</em>

<em>a = 15.4×10³ m/s².</em>

<em>Also given m = 0.145 kg</em>

<em>Substituting into equation 1,</em>

F = 0.145(15.4<em>×10³ )</em>

F = 2233 N

<em>Thus the force between the ball and the bat = 2233 N</em>

<em></em>

8 0
3 years ago
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